I don't think this is possible...
But if you mean 9 then the root is 3
Answer:
2). As x-> -∞, f(x)->∞
As x-> ∞, f(x)-> -∞
5). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
3). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
6). As x-> -∞, f(x)-> ∞
As x-> ∞, f(x)-> ∞
Step-by-step explanation:
I just watched a quick video so you can't completely trust me, but i tried my best. Hopefully someone more trustworthy for this comes in.
Answer:
97,99,101,103
Step-by-step explanation:
Let x = first odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+6 = 4th odd integer
Sum of 4 odd integers is 400
x+ (x+2) + (x+4)+(x+6) = 400
Combine like terms
4x +12 = 400
Subtract 12 from each side
4x+12-12 = 400-12
4x = 388
Divide by 4 on each side
4x/4 = 388/4
x=97
The first integer is 97
The 2nd is 97+2 =99
The third ix 97+4 = 101
The 4th is 97+6 = 103
(x - 2)^2 will always be positive and will have a minimum value of 0
so f(x) will have minimum of 2
Range is [2,∞)
3.305
+1.7
5.005
Line up the decimal points and add like you usually would add.
5.005 is the answer.
