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Aloiza [94]
2 years ago
9

A company produces candy bags that each hold about 528 cubic inches of candy. Each bag is filled with any mixture of lollipop ca

ndies and gummy bear candies. When a bag contains only lollipop candies, then it has about 361 candies. When a bag contains only gummy bear candies, then it has about 697 candies. Given any candy bag produced by this company, which of the following equations could relate the approximate number of lollipop candies, 7, in the bag and the approximate number of gummy bear candies, g, in the bag? A company produces candy bags that each hold about 528 cubic inches of candy . Each bag is filled with any mixture of lollipop candies and gummy bear candies . When a bag contains only lollipop candies , then it has about 361 candies . When a bag contains only gummy bear candies , then it has about 697 candies . Given any candy bag produced by this company , which of the following equations could relate the approximate number of lollipop candies , 7 , in the bag and the approximate number of gummy bear candies , g , in the bag ?​
Mathematics
1 answer:
enyata [817]2 years ago
3 0

361 lollipop candies or 697 gummy bear candies fills the bag of volume 528 in.³, which gives the following possible equation;

  • 1.46•l + 0.76•g = 528

<h3>How can the correct equation be found?</h3>

Volume of candy bag = 528 in.³

Number of lollipop candies the bag can hold = 361 candies

Number of gummy bear candies the bag can hold = 697 candies

Therefore;

1 \: lollipop =  \frac{528}{361}  =  1.46

1 \: gummy \: bear =  \frac{528}{697}  =  0.76

Which gives the following equation;

  • 1.46•l + 0.76•g = 528

Learn more about writing equations here:

brainly.com/question/18713037

#SPJ1

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HURRY PLEASE
klasskru [66]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

y=0,\:x=6

Step-by-step explanation:

Considering the system of the equations

\begin{bmatrix}2x-7y=12\\ -x+15y=-6\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:2x-7y=12

2x-7y+7y=12+7y

2x=12+7y

Divide both sides by 2

\frac{2x}{2}=\frac{12}{2}+\frac{7y}{2}

x=\frac{12+7y}{2}

\mathrm{Subsititute\:}x=\frac{12+7y}{2}

\begin{bmatrix}-\frac{12+7y}{2}+15y=-6\end{bmatrix}

-\frac{12+7y}{2}+15y=-6

\mathrm{Multiply\:both\:sides\:by\:}2

-\frac{12+7y}{2}\cdot \:2+15y\cdot \:2=-6\cdot \:2

-\left(12+7y\right)+30y=-12

-12+23y=-12

-12+23y+12=-12+12

23y=0

\mathrm{Divide\:both\:sides\:by\:}23

\frac{23y}{23}=\frac{0}{23}

y=0

\mathrm{For\:}x=\frac{12+7y}{2}

\mathrm{Subsititute\:}y=0

x=\frac{12+7\cdot \:0}{2}

x=\frac{12}{2}

x=6

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

y=0,\:x=6

4 0
3 years ago
The ages of two girls are in the ratio of 2:3 . 6 years hence the ratio of the girls will be 11 : 13 find their present age .​
erik [133]
Is the question right?
6 0
2 years ago
What is the area of the triangle?
nalin [4]

Answer:

108

Step-by-step explanation:

base times hight i think its been a while since i looked at the area of a triangle

5 0
3 years ago
Read 2 more answers
Suppose the average yearly salary of an individual whose final degree is a​ master's is ​$46 thousand less than twice that of an
seraphim [82]

Answer:

The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.

Step-by-step explanation:

In order to solve this problem we first need to attribute variables to the unkown quantities. We will call the average salary of Master's "x" and the average salary of a Bachellor's "y". The first information the problem gives us is:

x = 2*y - 46

The second one is:

x + y = 113

We now have two equations and two variables, so we can solve the system. To do that we will use the value for x from the first equation on the second one. We have:

2*y - 46 + y = 113

3*y = 113 + 46

3*y = 159

y = 159/3 = 53

x = 2*(53) - 46 = 60

The average sallary of a Master's is 60 thousand and of a Bachellor's is 53 thousand.

3 0
3 years ago
How do you find the answer so confused
alexandr402 [8]
For which question, I can help,
<span>for number 9, parallel lines have the same exact slope, so divide each of them by to isolate the y and then see if the slope (number multiplied by x) is the same as the other problems . PS: focus on the slope, rest of equation doesn't matter in this question</span>
5 0
3 years ago
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