Question

The width of a rectangular garden is 8 feet longer than 4 times its length. If the garden's perimeter is116 feet, what are the dimensions of the garden?Length =feetWidth =feet

Answer 1

SOLUTION:

Step 1:

The length of a rectangular garden is 8 feet longer than its width.

If the garden's perimeter is 184 feet.

What is the area of the garden in square feet?

Step 2:

L = length

W = width

L = W+8

P = perimeter

P = 2(L+W)

P =184 (given)

Substitute L=W+8 in the perimeter equation

2( (W+8) + W ) = 184

(W+8) +W = 92

2W + 8 = 92

2W = 84

W = 42 ft ( Width = 8 feet )

L = W+8

L = 42+8

L = 50 ft ( Length = 50 feet )

Always check your work.

In this case, check the perimeter.

2(L+W) = ?

2(50+42) = 184 feet.

CONCLUSION:

Then, the question says:

It asks for the area in square feet.

A = Area

A = L*W

A = 50 ft * 42 ft

A = 2100 sq ft.

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