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Arlecino [84]
3 years ago
15

A Square yellow rug has a red square in the center. The side length of the red square is X inches. The width of the yellow band

that's surrounds the red square is 6 inches. What is the area of the yellow band?
Mathematics
1 answer:
Mariana [72]3 years ago
4 0

Answer: The area of yellow band is 24x+144 sq. inches.

Step-by-step explanation:

Let the side length of the red square be 'x' inches

Width of the yellow band surrounds the red square = 6 inches

So, Length of  band would be

6+x+6=x+12

Width of  band would be

6+x+6=x+12

So, Area of the yellow band would be

\text{Area of whole band}-\text{Area of red square}\\\\=(x+12)\times (x+12)-x^2\\\\=(x+12)^2-x^2\\\\=x^2+144+24x-x^2\\\\=24x+144

Hence, the area of yellow band is 24x+144 sq. inches.

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in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
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