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saul85 [17]
4 years ago
12

Spheres that have the same length radi are called concentric. true false

Mathematics
2 answers:
Lyrx [107]4 years ago
8 0
False false false false
timofeeve [1]4 years ago
4 0

Answer:

Falsa

Step-by-step explanation:

Concentric circles share the Same center

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The number of surface flaws in a plastic roll used for auto interiors follows a Poisson distribution with a mean of 0.05 flaw pe
ElenaW [278]

Answer:

0.6065

Step-by-step explanation:

Probability mass function of probability distribution : P(X=x)=\frac{e^{-\lambda} \times \lambda^x}{x !}

a mean of 0.05 flaw per square foot

Each car contains 10 sq.feet of the plastic roll

Mean = 0.05

Mean = \lambda = 0.05 \times 10=0.5

We are supposed to find What is the probability that there are no flaws in a given car’s interior i.e,P(X=0)

Substitute the value in the formula

P(X=0)=\frac{e^{-0.5} \times (0.5)^0x}{0 !}

P(X=0)=\frac{e^{-0.5} \times (0.5)^0}{1}

P(X=0)=0.6065

Hence the probability that there are no flaws in a given car’s interior is 0.6065

5 0
3 years ago
Solve by substitution<br><br>3x - 3y = -6 <br><br> z=-3x-3y+9<br><br> -4x+5y+z=8
Vanyuwa [196]
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3 years ago
A sequence can be represented by the formula t(n)=6; t(n+1)=3*t(n). write the first 4 terms of the sequence. what would be an ex
Kamila [148]

Answer:

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Step-by-step explanation:...

8 0
4 years ago
Which expressions result in a negative number? Choose all answers that are correct. A. –84 ÷ 21 B. C. –7.3 – (–4.3) D. –4.2 • (–
elixir [45]
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6 0
3 years ago
Read 2 more answers
Each variable indicates different weights. Which weight can you find? Find it.
SOVA2 [1]

Answer:

We can only be certain that <em>a</em> weighs 12.

There are infinitely many possiblities for <em>b</em> and <em>c</em>.

Step-by-step explanation:

We have the equation:

a+b+c+a+c+b+a+c=12+a+a+b+b+c+c+c

Each variable indicates a weight.

We would like to determine the weights of each variable (if possible).

First, we can rearrange the equation to acquire:

(a+a+a)+(b+b)+(c+c+c)=12+(a+a)+(b+b)+(c+c+c)

We can combine like terms:

3a+2b+3c=12+2a+2b+3c

Notice that both sides have 2<em>b</em> and 3<em>c</em>. Therefore, it is possible for us to cancel them since each nullify the other side. So, we will subtract 2<em>b</em> and 3<em>c</em> from both sides. This yields:

3a=12+2a

Therefore, we can solve for <em>a</em>. Subtract 2<em>a</em> from both sides:

a=12

Hence, the weight of <em>a</em> is 12.

Using the newly acquired information, we can go back to our simplified equation:

3a+2b+3c=12+2a+2b+3c

Since <em>a</em> is 12:

3(12)+2b+3c=12+2(12)+2b+3c

Evaluate:

36+2b+3c=12+24+2b+3c

Simplify:

36+2b+3c=36+2b+3c

We can subtract 36 from both sides:

2b+3c=2b+3c

As you can see, this is a true statement.

Since this is a true statement, there are infinitely many possible values for <em>b</em> and <em>c</em>.

Therefore, the only weight we are <em>certain</em> of knowing is weight <em>a</em> weighing 12.

8 0
3 years ago
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