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katrin2010 [14]
2 years ago
14

30 points plus brainliest if answered right!

Mathematics
2 answers:
alukav5142 [94]2 years ago
8 0

Answer:

AC = 5, BC = √17, AB = √32

Explanation:

Given points: A(-3, -2), B(1, 2), C(2, -2)

Use distance between two points formula:

\sf Distance \ between \ two \ points = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC length:

\sf d =  \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2-(-3))^2 + (-2-(-2))^2}  = \sqrt{25+ 0}  = 5

BC length:

\sf d =  \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2-1)^2 + (-2-2)^2}  = \sqrt{1 + 16}  = \sqrt{17}

AB length:

\sf d =  \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(-3-1)^2 + (-2-2)^2}  = \sqrt{16 + 16}  = \sqrt{32}

Anettt [7]2 years ago
4 0

Answer:

The second choice.

Step-by-step explanation:

The length of AC must be equal to 5, since it is horizontally five units. We can rule out the first option.

Length BC cannot be the square root of 16, since that would be exactly 4 units. BC is slanted and does not represent a completely vertical line, so it is not a whole number. We can rule out the fourth option.

Length AB cannot be a whole number, being a slanted line that crosses a total of more than four units. Option three can be ruled out.

Therefore, we are left with the second option.

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It is not possible to prove one pair of triangles congruent and then use their congruent corresponding parts to prove another pa
borishaifa [10]

Answer:

true

The wording does not quite mean anything,

but what I think was meant to ask is

"if we use some parts of two triangles to prove they are congruent,

can we then use that to prove that

a pair of corresponding parts not used before are congruent?"

The answer is

Yes, of course,

Corresponding Parts of Congruent Triangles are Congruent,

which teachers usually abbreviate as CPCTC.

For example, if we find that

side AB is congruent with side DE,

side BC is congruent with side EF, and

angle ABC is congruent with angle DEF,

we can prove that triangles ABC and DEF are congruent

by Side-Angle-Side (SAS) congruence.

We then, by CPCTC, can conclude that other pairs of corresponding parts are congruent:

side AB is congruent with side DE,

angle BCA is congruent with angle EFD, and

angle CAB is congruent with angle FDE.

It was possible (by CPCTC) to prove those last 3 congruence statements,

after proving the triangles congruent.

The expected answer is FALSE.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
At a company picnic, 1/2 of the people are employees. 2/5 are employees' spouses. What percent are neither?​
kupik [55]

Answer:

10% of the people at the picnic are neither.

Step-by-step explanation:

To get the answer,

1/2 + 2/5 = 9/10

10/10 - 9/10 = 1/10

1/10 = 10%

Thanks, I hope I got this right!

7 0
3 years ago
Please answer if you know the answer.<br> Find x and give reasons.
gregori [183]
Here’s the answer, hope it helps. Btw these are screenshots from someone else’s work not mine

6 0
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M&lt;1 and m&lt;2 are vertical angles if m&lt;1 = 106° and M&lt;2 equals 20x - 14 find M&lt;2
just olya [345]

Answer:

Answer:

m∠2= 86

Step-by-step explanation:

since they are vertical angles, that means they are both equal to eachother.

so lets set them equal!

17x+1=20x-14

17x+15=20x

15=3x

x=5

now input x into m∠2

m∠2 = 20(5) – 14 = 86

Step-by-step explanation:

5 0
3 years ago
(05.01)
baherus [9]

Answer:

Always

Step-by-step explanation:

6 0
3 years ago
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