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dusya [7]
3 years ago
13

A line segment has an endpoint at (4,6). If the midpoint of the line segment is (1,5), what are the coordinates of the point at

the other end of the line segment
Mathematics
1 answer:
IrinaK [193]3 years ago
8 0

Answer:

(-2 , 4)

Step-by-step explanation:

(x_1 ,y_1)= (4,6)\\(x,y)=(1,5)\\\\x = \frac{x_1+x_2}{2}\\ \\y = \frac{y_1+y_2}{2}\\ \\1 = \frac{4+x_2}{2}\\Cross \:Multiply\\2 \times 1 = 4+x_2\\2 = 4+x_2\\2-4 =x_2\\\\x _2=-2\\\\\\y =\frac{y_1+y_2}{2} \\5 = \frac{6+y_2}{2}\\ \\Cross \:Multiply\\5 \times 2 = 6+y_2\\10 =6+y_2\\10-6 =y_2\\4 =y_2\\\\y_2 =4\\\\(x_2,y_2) = (-2,4)

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What is the most precise name for quadrilateral ABCD with vertices A(–5,2), B(–3, 5),C(4, 5),and D(2, 2)?
bonufazy [111]

Answer: ABCD is a parallelogram.

Step-by-step explanation:

First we plot these point on a graph as given in attachment.

From the attachment we can observe that AD || BC || x-axis .

also, AB ||CD, that will make ABCD a parallelogram ,  but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".

Mid point of AC= (\dfrac{-5+4}{2},\dfrac{2+5}{2})=(\dfrac{-1}{2},\dfrac{7}{2})

Mid point of BD= (\dfrac{-3+2}{2},\dfrac{5+2}{2})=(\dfrac{-1}{2},\dfrac{7}{2})

Thus, Mid point of AC=Mid point of BD

i.e. diagonals bisect each other.

That means ABCD is a parallelogram.

8 0
3 years ago
How do u do 2 over 3 =A over 60 PLZ NO LINKS THANKS
Ivanshal [37]

Hey there!

2/3 = a/30

First: you have to CROSS MULTIPLY the given numbers

2(30) = 3(a)

2(30) = 60

3(a) = 3a

New EQUATION: 3a = 60

Second: DIVIDE 3 to BOTH SIDES

3a/3 = 60/3

CANCEL out: 3/3 because that gives you 1

KEEP: 60/3 because that helps you solve for your a-value

60/3 = a

60/3 = 20

Therefore, your answer is: a = 20

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

6 0
2 years ago
Mel used partial quotients to find the quotient of 378 divided by 3.What could be the partial quotient that Mel found?
Genrish500 [490]

Answer:

The partial quotients are 100, 20 and 6. The quotient is 126.

Step-by-step explanation:

The dividend is 378 and the divisor is 3.

First find the factors of 3, near to 300.

3\times 1=3

3\times 10=30

3\times 100=300

The value 300 is less than 378, so record the partial quotient 100 and subtract 300 from 378. Repeat the same process until the dividend has been zero.

Now the remaining divide is 78.

First find the factors of 3, near to 78.

3\times 20=60

3\times 30=90

Since 90>78, therefore 30 is not a partial quotient. The value 60 is less than 78 , so record the partial quotient 20 and subtract 60 from 78.

Now the remaining divide is 18.

3\times 6=18

The number 6 is a partial quotient.

Therefore  partial quotients are 100, 20 and 6. Add the partial quotient to find quotient.

100+20+6=126

3 0
3 years ago
Mrs.Barkley has 75 feet ribbon. If each of the 18 students in her class gets an equal length of ribbon, how many inches of ribbo
Black_prince [1.1K]

Answer:

Each student would get 4 inches of ribbon


Step-by-step explanation:

Mrs. Barkley has 75 inches of ribbon and is splitting it between 18 students so you would divide 75 by 18. When you divide you get 4.166666... etc. So the answer would be 4

3 0
3 years ago
What is the range? 5,10,5,4,5,10,3,10<br> Help me pls
Nady [450]

Answer: the answer is 7

Step-by-step explanation: the lowest number is 3 and the biggest one is 10 so you substract 10-3 and you get 7

8 0
3 years ago
Read 2 more answers
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