For x intercepts, plug in 0 for y.
0 = (x^2) - 2x - 35
*factoring* = (x-7)(x+5)
x intercepts = 7,-5
As for the vertex, you can use the equation -b/2a for the x-coordinate of the vertex
so,
x = -b/2a = -(-2)/2 = 1
then just find the y value by plugging it back in to the equation.
y = ((1)^2) - 2(1) - 35
= -36
so, vertex is at (1,-36)
Answer:
1/125, 1/625, 1/3125
Step-by-step explanation:
a8=25*(1/5)^7=25/78125=1/3125
If we can match teh bases we can solve
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22
Where a, b, and c are real numbers and a ≠ 0 .
The quadratic term is ax
2
, the linear term is
bx, and the constant term is c. Quadratic
functions have degree two. The graph of a
quadratic function is called a parabola. If
a < 0, then the parabola opens downward,
like function g. If
a > 0, then the parabola
opens upward like function f. If
the parabola opens upward, then
the vertex is the point whose yvalue
is the minimum value of f.
If the parabola opens downward,
then the vertex is the point
whose y-value is the maximum
value of f. The vertical line that
goes through the vertex is called
the axis of symmetry of the
parabola.
