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Anon25 [30]
3 years ago
11

A population of lizards decreases exponentially at a rate of 12.5% per year. What is the equivalent monthly rate to the nearest

hundredth of a percent?
a. 0.20%
b. 1.04%
c. 1.11%
d. 1.23%
Mathematics
2 answers:
lapo4ka [179]3 years ago
5 0

Answer:

1.04%

Step-by-step explanation:

We are given that there is 12.5% decrease in lizards exponentially in 1 year i.e. 12 months.

Therefore, the percentage decrease in lizards per month will be 12.5% divided by 12.

i.e. \frac{12.5}{12} = 1.0416667%

So, the percentage decrease per month is 1.0416667%

Hence, rounding 1.0416667% to nearest hundredth, we get 1.04%

soldier1979 [14.2K]3 years ago
3 0

Answer:1.04%


Step-by-step explanation:

12.5/12 = 1.04166667

when we round this to the nearest hundredth its 1.04%


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A 40% dye solution is to mixed with a 53% dye solution to get 260L of a 50% solution. How many liters of the 40% and 50% solutio
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<h3>60 liters of 40 % dye solution is mixed with 200 liters of 53 % dye solution to get 260 liters of 50 % dye solution</h3><h3><u>Solution:</u></h3>

From given,

Final solution is 260 liter

Let x be the liters of 40 % dye solution

Then, (260 - x) is the liters of 53 % dye solution

Therefore, according to question,

x liters of 40 % dye solution is mixed with (260 - x) liters of 53 % dye solution to get 260 liters of 50 % dye solution

<h3><u>Thus we frame a equation as:</u></h3>

40 % of x + 53 % of (260 - x) = 50 % of 260

Solve for "x"

\frac{40}{100} \times x + \frac{53}{100} \times (260-x) = \frac{50}{100} \times 260\\\\0.4x+ 0.53(260-x) = 0.5 \times 260\\\\0.4x + 137.8 - 0.53x = 130\\\\0.13x = 137.8 - 130\\\\0.13x = 7.8\\\\Divide\ both\ sides\ by\ 0.13\\\\x = 60

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