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Anon25 [30]
3 years ago
11

A population of lizards decreases exponentially at a rate of 12.5% per year. What is the equivalent monthly rate to the nearest

hundredth of a percent?
a. 0.20%
b. 1.04%
c. 1.11%
d. 1.23%
Mathematics
2 answers:
lapo4ka [179]3 years ago
5 0

Answer:

1.04%

Step-by-step explanation:

We are given that there is 12.5% decrease in lizards exponentially in 1 year i.e. 12 months.

Therefore, the percentage decrease in lizards per month will be 12.5% divided by 12.

i.e. \frac{12.5}{12} = 1.0416667%

So, the percentage decrease per month is 1.0416667%

Hence, rounding 1.0416667% to nearest hundredth, we get 1.04%

soldier1979 [14.2K]3 years ago
3 0

Answer:1.04%


Step-by-step explanation:

12.5/12 = 1.04166667

when we round this to the nearest hundredth its 1.04%


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Solve each inequality, and then drag the correct solution graph to the inequality.
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The correct solution graph to the inequalities are

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(NOTE: The graphs are labelled A, B and C from left to right)

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First, clear the brackets,

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For the second inequality

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For the third inequality,

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1.6x + 12.8\geq 38.4

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\frac{1.6x}{1.6}\geq  \frac{25.6}{1.6}

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The first graph (A) shows x\leq  -8 and this matches the 2nd inequality

The second graph (B) shows x \geq  16 and this matches the 3rd inequality

The third graph (C) shows x > 9 and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

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1.6(x+8)\geq 38.4  →  B

Learn more here: brainly.com/question/17448505

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