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gladu [14]
3 years ago
12

The difference of 2 and the product of 3and k

Mathematics
1 answer:
allsm [11]3 years ago
7 0
2-3k because the difference between something means it is subtraction and the product of 3 and k would just be 3k since you don't know what k is.                                  
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2×+2=6<br><img src="https://tex.z-dn.net/?f=5%20x%20%2B%204%20%3D%208" id="TexFormula1" title="5 x + 4 = 8" alt="5 x + 4 = 8" al
amm1812

Answer:

Step-by-step explanation:

hello

2x+2=6 2x+2-2=6-2 \ \ \ substract \ \ 2\\ 2x = 4  \dfrac{2x}{2}=x=\dfrac{4}{2}=2 \ \ \ divide \ \ by  \ \ 2\\

so the solution is 2

5x+4=8 5x+4-4=8-4 \ \ \ substract \ \ 4\\ 5x = 4  \dfrac{5x}{5}=x =\dfrac{4}{5} \ \ \ divide \ \ by  \ \ 5

so the solution is 4/5

hope this helps

3 0
3 years ago
Read 2 more answers
What is F(7) if (x) = 5x
Law Incorporation [45]
The answer is 35.
........
3 0
2 years ago
Read 2 more answers
Layana’s house is located at (2 and two-thirds, 7 and one-third) on a map. The store where she works is located at (–1 and one-t
NeTakaya

We have been given that Layana’s house is located at (2\frac{2}{3}, 7\frac{1}{3}) on a map. The store where she works is located at (-1\frac{1}{3}, 7\frac{1}{3}).

We are asked to find the distance from Layana’s home to the store

We will use distance formula to solve our given problem.

Let us convert our given coordinates in improper fractions.

2\frac{2}{3}\Rightarrow \frac{8}{3}

7\frac{1}{3}\Rightarrow \frac{22}{3}

-1\frac{1}{3}\Rightarrow -\frac{4}{3}

Now we will use distance formula to solve our given problem.

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Upon substituting coordinates of our given point in above formula, we will get:

D=\sqrt{(\frac{22}{3}-\frac{22}{3})^2+(\frac{8}{3}-(-\frac{4}{3}))^2}

D=\sqrt{(0)^2+(\frac{8}{3}+\frac{4}{3})^2}

D=\sqrt{0+(\frac{8+4}{3})^2}

D=\sqrt{(\frac{12}{3})^2}

D=\sqrt{(4)^2}

D=4

Therefore, the distance from Layana's home to the store is 4 units and option A is the correct choice.

3 0
3 years ago
Read 2 more answers
Instructions: The polygons in each pair are similar. Find the missing side length.
adoni [48]

Answer:

20

Step-by-step explanation:

<u>25 </u>  =     <u> x</u>

20           16

(25*16)/20 = 20

4 0
2 years ago
A 40% sugar solution is added to an 85% sugar solution to create 1800 mL of a 60% solution. How much of each solution is used? (
denis-greek [22]

Answer:

Number of ml of 40% sugar = x = 1000mL

Number of ml of 85% sugar used = y = 800mL

Step-by-step explanation:

Let the

Number of ml of 40% sugar = x

Number of ml of 85% sugar used = y

From the above question, our system of equations is given as:

x + y = 1800mL ....... Equation 1

x = 1800 - y

40% × x + 85% × y = 60% × 1800mL

0.4x + 0.85y = 1080.... Equation 2

We substitute 1800 - y for x in Equation 2

0.4(1800 - y) + 0.85y = 1080

720 - 0.4y + 0.85y = 1080

- 0.4y + 0.85y = 1080 - 720

0.45y = 360

y = 360/0.45

y = 800mL

Solving for x

x = 1800 - y

x = 1800 - 800

x = 1000mL

Therefore,

Number of ml of 40% sugar = x = 1000mL

Number of ml of 85% sugar used = y = 800mL

4 0
2 years ago
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