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gladu [14]
3 years ago
12

The difference of 2 and the product of 3and k

Mathematics
1 answer:
allsm [11]3 years ago
7 0
2-3k because the difference between something means it is subtraction and the product of 3 and k would just be 3k since you don't know what k is.                                  
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Can someone Help with this question
inn [45]

Answer:

B 12

Step-by-step explanation:

  • manuel ate 1/3X
  • His brother ate 1/4X
  • leftover is 5
  • total is X

manuel+brother+leftover=X

x/3+x/4+5=x

7x+60/12=x

  • cross multiply

7x+60=12x

  • collect like terms

60=12x-7x

60=5x

  • divide both by 5

x=60/5

x= 12

5 0
3 years ago
Sinxcosxtanx=1-cos^2x
ycow [4]

Step-by-step explanation:

sin  x \: cos  x \: tanx = 1 -  {cos}^{2} x \\ LHS \\= sin  x \: cos  x \: tanx \\  =sin  x \: cos  x \: \times  \frac{sin  x}{cos  x}  \\  = sin  x \: \times  \frac{sin  x}{1} \\  ={sin}^{2}  x \\  = 1 -  {cos}^{2} x \\  = RHS \\  \therefore \: sin  x \: cos  x \: tanx = 1 -  {cos}^{2} x \\ Hence \: Proved.

7 0
3 years ago
Which numbers have a digit in the ones place that is 1/10 the value of the digit in the tens place
liq [111]

Answer:

4,099  and 5,011

Step-by-step explanation:

This problem can be solved by taking options one by one.

Option (1) : 4,099  

Digit in ones place = 9

The value of the digit in tens place = 90

\dfrac{9}{90}=\dfrac{1}{10}. It is correct.

Option (2) : 4,110

Digit in one places = 0

The value of the digit in tens place = 10

It is incorrect.

Option (3) : 5,909

Digit in one places = 9

The value of the digit in tens place = 0

It is again incorrect.

Option (4) : 5,011

Digit in one places = 1

The value of the digit in tens place = 10

\dfrac{1}{10}. It is correct.

Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.

7 0
3 years ago
A student is 90 cm tall and growing at a rate of 3 cm per month. At this rate, in how many months will the student grow to a hei
Zolol [24]

Answer:

14 months

Step-by-step explanation:

14x3=42

42+90= 132

6 0
2 years ago
I need #14 done by tomorrow around 9-10:00. Thank you so much if you do. God bless you :3
Vinvika [58]

Answer:

A) $ \frac{1}{5} $

B) - 5

C) Not Possible

D) 5

E) $ \frac{-1}{5} $

  • Step-by-step explanation:
  • All integers are rational numbers. But not all rational numbers are integers.
  • All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $ \frac{p}{q} $.

From, the options $ \frac{1}{5} $ would fit this description.

I am a rational number and an integer but not a whole number.

This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.

I am a whole number but not an integer.

This is clearly not possible because all whole numbers are a subset of integers.

I am a rational number, a whole number and an integer.

This means it is a positive integer. 5 would fit this description.

I am a rational number but not an integer; located on the left side of 0.

This means it is a negative number. $ -\frac{1}{5} $ should be the answer.

3 0
3 years ago
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