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steposvetlana [31]
3 years ago
8

How much water can be held by a cylindrical tank with a radius of 12 feet and a height of 30 feet?

Mathematics
1 answer:
aniked [119]3 years ago
5 0

your answer is 13,564.8 cubic feet

i just took the test

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5 pounds 80 cents $1.40 per pound
tensa zangetsu [6.8K]

What’s your question?

6 0
3 years ago
Brian cut a piece of cardboard in the shape of a trapezoid the area of the cut out is 43.5 cm² if the bases are 6 cm And 8.5 cm
Likurg_2 [28]

Answer: the height of the trapezoid is 6 cm

Step-by-step explanation:

The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of The bases are the 2 sides of the trapezoid which are parallel with one another.

h represents the height of the trapezoid.

From the information given,

a = 6 cm

b = 8.5 cm

If the area of the cut out is 43.5 cm², then

53.5 = 1/2(6 + 8.5)h

Cross multiplying by 2, it becomes

43.5 × 2 = (6 + 8.5)h

87 = 14.5h

h = 87/14.5 = 6 cm

8 0
3 years ago
What is the value of x
Gemiola [76]

9514 1404 393

Answer:

  x = 10

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation ...

  Sin = Opposite/Hypotenuse

  sin(30°) = 5/x

Solving for x, we get ...

  x = 5/sin(30) = 5/0.5

  x = 10

_____

It can be helpful to remember that the side ratios in a 30°-60°-90° triangle are ...

  1 : √3 : 2

That is, the hypotenuse is 2 times the length of the side opposite the 30° angle. Here, that means x = 2×5 = 10, as we found above.

6 0
2 years ago
During a drought, the water level in a reservoir dropped 3 in. each week for 5 straight weeks. Express the overall change in wat
aliina [53]

Answer:

v = -3w

Step-by-step explanation:

water level/volume = -3 x weeks

v = -3w

6 0
2 years ago
Find all critical points of the given plane autonomous system. (Enter your answers as a comma-separated list.) x′ = x 12 − x − 1
Andru [333]

Answer:

the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

Step-by-step explanation:

To consider the autonomous system

x' =x (12 -x - \dfrac{1}{2})

y' = y( 20 -y - x)

The critical points of the above system can be derived by replacing x' = o and y' = 0.

i.e.

x' =x (12 -x - \dfrac{y}{2}) = 0

\dfrac{x}{2} (24 -2x - y) = 0

x = 0 or 24 - 2x - y = 0     ----- (1)

Also

y' = y( 20-y-x) = 0

y( 20 -y - x) = 0

y = 0 or 20 - y - x = 0  -----   (2)

By solving (1) and (2);

we get x = 4 and y = 16

Suppose x = 0 from (2)

y = 20

Also;

if y = 0 from (1)

x = 12

Thus, the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

6 0
2 years ago
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