Rewrite 2x^2+x=15 as <span>2x^2+ x - 15 = 0. Use your favorite method to solve this for x. I prefer synthetic div., so will check out whether or not 2 is a root:
____________
2 / 2 1 -15
4 10
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2 5 -5 Since there is a non-zero remainder, 2 is NOT a root. Eliminate the 3rd answer choice.
Try -3. If used as a divisor in synth. div., will the remainder be zero or not zero? If zero, then -3 is a solution / root.
And so on.</span>
Answer:
B
Step-by-step explanation:
GI is made up of the segments GH and HI. In other words:
We know that GH is 2 and GI is 7. Substitute:
Subtract 2 from both sides:
So, our answer is B.
And we're done!
(s o t)(-7) = s(t(-7)) = s(3(-7)) = s(-21) = 2 - (-21)^2 = 2 - 441 = -439
Concentric circles because if a line is tangent to one circle, it would only intersect teh other
2m+3=23
2m=20
m=10
let me know in the comments if you need further explanation :)
