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Damm [24]
3 years ago
10

Given two different circles O and Q, which of the following cases presents two circles with no (zero) common tangents?

Mathematics
2 answers:
devlian [24]3 years ago
6 0

concentric circles

Answer:

concentric circles

Step-by-step explanation:

borishaifa [10]3 years ago
3 0
Concentric circles because if a line is tangent to one circle, it would only intersect teh other 
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What’s the square root of 108 a to the 7th power b to the 5th power
MissTica

Answer:

Step-by-step explanation:

Factor all the factors making up the square root.

108: 2*2*3*3*3

a^7: a*a*a*a*a*a*a

b^5:b * b * b * b * b

The rule for taking a square root of this is

For every pair, you get to take one number outside the root sign and throw the other one away.

2*3*a * a * a* b * b√(3*a * b)

6a^3b^2 * √(3*a*b)

4 0
3 years ago
Evaluate this expression <br> (-7--9)*(8+2)
Marizza181 [45]
Before we get started, it is good to remember PEMDAS - the acronym that tells you the order to carry out equations.

P = parentheses
E = exponents
M = multiplication
D = division
A = addition
S = subtraction

Knowing this, we should start by doing the equations <em>within </em>each parentheses.
 
(-7 - -9) *(8 + 2)
 (2) *(10)

So we did the addition and subtraction pieces within each group leaving us with the above equation. Now let's multiply:

(2)*(10) = 20

20 is the answer.
5 0
3 years ago
What is the value of AAA when we rewrite \left(\dfrac {6}{17}\right)^{9x}( 17 6 ​ ) 9x (, start fraction, 6, divided by, 17, end
sineoko [7]

We have been given an expression \left(\dfrac {6}{17}\right)^{9x}. We are asked to find the value of A when rewrite our given expression as A^{x}.

To solve our given problem, we will use exponent properties.

Using exponent property a^{mn}=(a^m)^n, we can rewrite our given expression as:

\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}

Now, we will compare our expression with  A^{x}.

Upon comparing \left(\left(\dfrac {6}{17}\right)^9\right)^{x} with A^{x}, we can see that A=\left(\dfrac {6}{17}\right)^9.

Therefore, the value of A is \left(\dfrac {6}{17}\right)^9.

We can further simplify \left(\dfrac {6}{17}\right)^9 as:

\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}

6 0
3 years ago
I WILL GIVE BRAINLIEST PLEASE HELP!!!
luda_lava [24]

Answer:

Step-by-step explanation:

interchange x and y

y= 1/(x - 2)

x = 1 / (y - 2)      Multiply both sides by y - 2

x(y - 2) = 1          Remove the brackets

xy - 2x = 1          Add x to both sides

xy = 1 + 2x         Divide by x

y = (1 + 2x)/x

The brackets have been destroyed. The answer is as I've given it.

y = (1/x) + 2

5 0
3 years ago
Which expressions are a factor of -48xyz -24xy +40
wariber [46]
A. 4 (is the only factor for expression -48xyz -24xy +40)
8 0
3 years ago
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