Given f(x) = 8x+1 2x-9 O As x-00, f(x) → 9; as x → ∞o, f(x) → 9. -> - O As x-00, f(x) O As x-00, f(x) O As x-00, f(x) - - wha
t is the end behavior of the function? ->> -9; as x -4; as x ∞o, f(x) → -9. - ∞o, f(x) → -4. - 4; as x → ∞o, f(x) → 4. -> - Given f ( x ) = 8x + 1 2x - 9 O As x - 00 , f ( x ) → 9 ; as x → ∞o , f ( x ) → 9 . - > - O As x - 00 , f ( x ) O As x - 00 , f ( x ) O As x - 00 , f ( x ) - - what is the end behavior of the function ? - >> -9 ; as x -4 ; as x ∞o , f ( x ) → -9 . - ∞o , f ( x ) → -4 . - 4 ; as x → ∞o , f ( x ) → 4 . - > -
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Answer:
B'(3, 5)
Step-by-step explanation:
Rule for the translation of a point (x, y) by 'h' units left and 'k' units upwards,
(x, y) → (x - h, y + k)
If h = 4 and k = 3,
Following this rule coordinates of the image point of B will be,
B(7, 2) → B'(7 - 4, 2 + 3)
→ B'(3, 5)
Therefore, coordinates of the image point B' will be,
B'(3, 5)