Given f(x) = 8x+1 2x-9 O As x-00, f(x) → 9; as x → ∞o, f(x) → 9. -> - O As x-00, f(x) O As x-00, f(x) O As x-00, f(x) - - wha
t is the end behavior of the function? ->> -9; as x -4; as x ∞o, f(x) → -9. - ∞o, f(x) → -4. - 4; as x → ∞o, f(x) → 4. -> - Given f ( x ) = 8x + 1 2x - 9 O As x - 00 , f ( x ) → 9 ; as x → ∞o , f ( x ) → 9 . - > - O As x - 00 , f ( x ) O As x - 00 , f ( x ) O As x - 00 , f ( x ) - - what is the end behavior of the function ? - >> -9 ; as x -4 ; as x ∞o , f ( x ) → -9 . - ∞o , f ( x ) → -4 . - 4 ; as x → ∞o , f ( x ) → 4 . - > -
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Given the statement: The length of an aquarium, which has the form of a rectangular solid, is equal to 5 decimeters, and the width is 4/5 the length.
Since, aquarium is in the form of a rectangular solid.
Length of an aquarium(l) = 5 dm
Width of an aquarium(w)=
It is also given that when you put 40 liters of water into the aquarium, it was full to its volume.
Volume of Rectangular solid(V) is given by;
where l is the length , w is the width and h is the height of the rectangle respectively.
Volume(V) of an aquarium = liter.
Using volume formula to calculate the height(h);
Divide both sides by 20 we get;
h = 3 dm [ 1 liter = 1 cubic dm]
We have to find the what part of length makes up the height of the aquarium.
where l = 5 dm
therefore, part of the length makes up the height of the aquarium.