Point T is on line segment SU. Given ST=13 and TU=5, determine the length SU.
2 answers:
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Answer:
As Given △QRS is rotated about point P to △Q′R′S′ .
As we know after rotation by any angle of pre-image neither the shape nor size of the image changes, the image after rotation is congruent to pre image.
Out of the options given
→The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved.
→The corresponding angle measurements in each triangle between the pre-image and the image are preserved.
are true.
Part (a)
<h3>Answer: y1 and y3 are perpendicular</h3>This is because the two slopes 2 and -1/2 multiply to -1. Perpendicular slopes multiply to -1 assuming neither line is vertical or horizontal.
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Part (b)
Graph each line to see where they cross. The three points of intersection are
(0,4)
(2,-2)
(4,2)
The order of the points doesn't matter.
You could also form three systems of equations pairing up the equations, and solving each system. That way you can find the points of intersection. Graphing may be a better and faster route in my opinion. See the diagram below.
