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nevsk [136]
4 years ago
12

Point T is on line segment SU. Given ST=13 and TU=5, determine the length SU.

Mathematics
2 answers:
KonstantinChe [14]4 years ago
6 0

Answer:

We are given the lengths of the two segments of the line. Using the addition postulate we can obtain the segment of the entire line.

Did you draw out the diagram. We know that the three points are collinear.

Hope this helps

Step-by-step explanation:

RSB [31]4 years ago
5 0

Answer:

SU=18

Step-by-step explanation:

The segments ST and TU make up the line segment SU. Add the values to find SU:

ST+TU=SU\\\\13+5=18

The length of SU is 18.

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A certain model of automobile has its gas mileage (in miles per gallon, or mpg) normally distributed, with a mean of 28 mpg and
Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

We are finding the probability, which is a percentage, of each of these intervals on our standard bell curve. In order to find this percentage, we need to find the z-score that provides this percentage. To find the z-score:

z=\frac{x_i-\bar{x}}{\sigma} which is the number in question minus the mean, all divided by the standard deviation. We're first looking for the probability that the gas mileage on a certain model of car is less than 26 mpg.

To find this z-score:

z=\frac{26-28}{4}=-.5 Depending upon which table you look at for the z-score determines how you will find it. The z-score that measure from the value and to the left of it is what we need. This decimal is .3085375, or 30.8538%.

Onto b., which is for the percentage of cars that have gas mileage over 34 mpg. Find the z-score, and this time, we look to the right of the value for the percentage:

z=\frac{34-28}{4}=1.5 and to the right of 1.5 standard deviations we will find .0668072, or 6.68072%

Then finally c., which wants the probability that the gas mileage on one of these cars is greater than 22 but less than 34 mpg. To do this we have to find the z-scores of each and then do some subtracting. First the z-scores:

z=\frac{22-28}{4}=-1.5 The percentage of data that lies to the right of that z-score is .9331927

The z-score for the other value, 34, was already found as 1.5, having .0668072 of the data to the right of that z-score. We subtract the smaller from the larger to determine what's left in-between:

.9331972 - .0668072 = .86639, or as a percentage, 86.639% of the cars fall into this interval for gas mileage.

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