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Dominik [7]
3 years ago
15

the length of a rectangle is 2 more than the width and the perimeter is 80. find the dimensions of the rectangle

Mathematics
2 answers:
4vir4ik [10]3 years ago
5 0
Let width = x  then
2x+ 2(x + 2) = 80
4x + 4 = 80
4x = 76
x = 19  

so the width is 19 and the length is 21 answer
Rashid [163]3 years ago
5 0
Let L represent the length of the rectangle
let W represent the width of the rectangle
the length is 2 more than the width
L = 2 + W
Let the Perimeter = P
P = 2(L + W)
substitute L = 2 + W, and P =80 in the Formula above
80 = 2( 2 + W + W)
80 = 2(2 + 2W)
80 = 4 + 4W
4W = 80 - 4
4W = 76
W = 19
L = 2 + W
L = 2 + 19
L = 21
the width is 19
the length is 21
pls mark me as brainliest
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Answer:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

p(A) = \frac{5}{7}

p(B) = \frac{2}{3}

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

P(A|B) = P(A)

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And for this special case we want to find this probability:

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And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

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3 years ago
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