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Dominik [7]
3 years ago
15

the length of a rectangle is 2 more than the width and the perimeter is 80. find the dimensions of the rectangle

Mathematics
2 answers:
4vir4ik [10]3 years ago
5 0
Let width = x  then
2x+ 2(x + 2) = 80
4x + 4 = 80
4x = 76
x = 19  

so the width is 19 and the length is 21 answer
Rashid [163]3 years ago
5 0
Let L represent the length of the rectangle
let W represent the width of the rectangle
the length is 2 more than the width
L = 2 + W
Let the Perimeter = P
P = 2(L + W)
substitute L = 2 + W, and P =80 in the Formula above
80 = 2( 2 + W + W)
80 = 2(2 + 2W)
80 = 4 + 4W
4W = 80 - 4
4W = 76
W = 19
L = 2 + W
L = 2 + 19
L = 21
the width is 19
the length is 21
pls mark me as brainliest
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P(V^{C}∪W^{C}) = P(V^{C}) + P(W^{C}) - P(V^{C}∩W^{C})

Isolating the probability that interests us:

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Where P(V^{C}∪W^{C}) = 1 - 0.04 = 0.96

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amid [387]

Answer:

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