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Gemiola [76]
2 years ago
6

Cho Q(x)=x^2+mx-12.Biết Q(-3)=0.tìm nghiệm còn lại

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
3 0

Answer: m=-1.

Step-by-step explanation:

Q(x)=x^2+mx-12\ \ \ \ Q(-3)=0\ \ \ \ \ m=?\\Q(-3)=(-3)^2+m*(-3)-12=0\\9-3m-12=0\\-3m-3=0\\3m=-3\ |:3\\m=-1.

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8.1 = 0.9a, how do you solve?
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Answer:

a = 9

Step-by-step explanation:

Simplifying

8.1 = 0.9a

Solving

8.1 = 0.9a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-0.9a' to each side of the equation.

8.1 + -0.9a = 0.9a + -0.9a

Combine like terms: 0.9a + -0.9a = 0.0

8.1 + -0.9a = 0.0

Add '-8.1' to each side of the equation.

8.1 + -8.1 + -0.9a = 0.0 + -8.1

Combine like terms: 8.1 + -8.1 = 0.0

0.0 + -0.9a = 0.0 + -8.1

-0.9a = 0.0 + -8.1

Combine like terms: 0.0 + -8.1 = -8.1

-0.9a = -8.1

Divide each side by '-0.9'.

a = 9

Simplifying

a = 9

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