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pochemuha
2 years ago
15

Suppose that a dog, a goat, and a bag of tin cans are to be transported across a river in a ferry that can carry only one of the

se three items at once (along with a ferry driver). If the dog and goat cannot be left alone on a shore when the driver is not present, nor can the goat and tin cans, find a scheme for getting all across the river.
Mathematics
1 answer:
Bingel [31]2 years ago
4 0

Answer:

The task is explained in detail below.

Step-by-step explanation:

We know that  a dog, a goat, and a bag of tin cans are to be transported across a river in a ferry that can carry only one of these three items at once (along with a ferry driver).  

The driver will first transport the goat to the other shore and then return empty. Then they will take a bag of tin and transport it to the other shore, and then they will return with the goat to their original place.  

Then he will leave the goat there and take a dog and carry it to the other shore and then return empty.

And eventually they will take the goat and transport it to the other shore.

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3/4 c - 7/12 + 7/24 c + 2/3 - 1/6 c
CaHeK987 [17]

Answer:

c+1/12

Step-by-step explanation:

18/24c-7/12+7/24c+8/12-4/24c=c+1/12

8 0
2 years ago
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Solve for the indicated variable.<br><br> 2a + 2b = c for b<br><br> B = ?/?
kodGreya [7K]

Answer:

b =  c − 2a

     ------------

          2

Step-by-step explanation:

2a + 2b = c

2b = c − 2a

b =  c − 2a

     ------------

          2

7 0
3 years ago
2. A cake in the shape of a circus tent is used as a centerpiece at a celebration. The cake consists of a cylinder and a cone. T
SashulF [63]
1808.64

Hope this helped!
8 0
2 years ago
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Acone has a height of 7 ft and a radius of 4 ft. Which equation can find the volume of the cone?
Marina86 [1]

Answer:

Volume of the cone = 117.06\,feet^3

Step-by-step explanation:

Height of the cone = 7\,feet

Radius of the cone = 4\,feet

Volume of a cone is:

              \pi \times r^2\times \dfrac{h}{3}

As, \pi =\dfrac{22}{7} =3.14

Volume is:      

                 =3.14\times(4\times 4)\times \dfrac{7}{3}\\\\ =3.14\times 16 \times 2.33\\\\=3.14\times 37.28\\\\=117.06\,feet^3

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3 0
2 years ago
Please help with number 39
mr Goodwill [35]

You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation

... 3v + 7c = 4480

In intercept form, this equation is

... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480

Among other things, this tells us one solution is

... (v, c) = (0, 640)

The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.

The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)

We can also pick some number in between, say using 100 as the multiple

... (0 +100·7, 640 -100·3) = (700, 340)

In summary, your three solutions could be

... (visors, caps) = (0, 640), (700, 340), (1491, 1)

7 0
2 years ago
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