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2 years ago

Stage _____ of NREM sleep represents the beginning of actual sleep.

Biology

1 answer:

djyliett [7]2 years ago

7 0

Answer: B. Two

Explanation:

During the first stage, your body starts relaxing and falling into sleep. This is the lightest stage of sleep. You can wake easily during this stage, and are not "fully" asleep.

During the second stage, your body deepens into it's sleep, your heart rate decreases, your body temperature decreases, and more. This is the stage that "represents the beginning of actual sleep" which is the answer to your question.

During the third stage, your body is in a deeper state of sleep. Your muscles relax further, your breathing rate slows, and more.

During the fourth stage, your heart rate and body temperature rise again. Your brain is a bit more active, and your muscles start to "wake up" slowly again.

Read more about NREM sleep here:

brainly.com/question/14410334

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3 years ago

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A) In the Dunker population, the frequency of IB allele is 0.3 and the frequency of i allele is 0.4. In the general population, the frequency of IB allele is 0.1 and the frequency of i allele is 0.5.

If:
$I^{A}$ - the frequency of IA allele
 $I^{B}$ - the frequency of IB allele
 $i$ - the frequency of i allele

Then:
 $I^{A} I^{A}$ + $I^{A} i$ - the frequency of individuals with A blood type
 $I^{B} I^{B}$ + $I^{B} i$ - the frequency of individuals with B blood type
 $ii$ - the frequency of individuals with O blood type

Let's first take a look on the Dunker population:
$I^{A} = 0.3$
$ii=0.16
$

Since there is only one possible genotype for O individuals - ii - the frequency of the allele i is square root of the frequency of O individuals:
 $i= \sqrt{ii}$
⇒ $i = \sqrt{0.16}$
⇒ $i=0.4$

Now, we have the frequencies of two alleles ( $I^{A}$ and $i$ ). To calculate the frequency of $I^{B}$ allele, we will use the formula:
 $I^{A} + I^{B} + i = 1$
⇒ $I^{B} = 1- I^{A} - i$
⇒ $I^{B} = 1-0.3-0.4$
⇒ $I^{B} = 0.3$

Now, in the general population:
$I^{A} = 0.4$
$ii=0.25$

Similarly to the work for the Dunker population:
 $i= \sqrt{ii}$
⇒ $i = \sqrt{0.25}$
⇒ $i=0.5$

$I^{A} + I^{B} + i = 1$
⇒ $I^{B} = 1- I^{A} - i$
⇒ $I^{B} = 1-0.4-0.5$
⇒ $I^{B} = 0.1$


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mezya [45]

Answer:

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Explanation:

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