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algol [13]
2 years ago
7

Pls help me in this i really need help :( :)

Mathematics
1 answer:
Andrews [41]2 years ago
5 0

Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step:</u>

<u>First off, let's write the line in point-slope form:</u>

  \rm \hookrightarrow (y-y_0)=m(x-x_0)

  • (x₀, y₀) any random point on the line
  • 'm' is the value of the slope

<u>Let's calculate the slope:</u>

 \rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}

  • (x₁, y₁): any random point on the line                                     ⇒   (-2, -6)
  • (x₂,y₂): any random point on the line that is not (x₁, y₁)         ⇒   (2, -3)

                 \rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}

<u>Now that we found the slope, let's put it into the point-slope form</u>

  ⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

     (y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)

<u>The equation, however, could also be put into 'slope-intercept form'</u>

     ⇒ gotten by isolating the 'y' variable to the left

          y = \frac{3}{4}x-\frac{9}{2}  

<u>Answer:</u>y = \frac{3}{4}x-\frac{9}{2} or y+3=\frac{3}{4} (x-2)

   *<em>Either equations work, put the one that you are the most familiar with</em>

Hope that helps!

#LearnwithBrainly

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Complete the statements.
spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

3tan^2(x)-1 =0

Lets assume tan(x) = u

3u^2(x)-1 =0

Now we solve for 'u'

add 1 on both sides

3u^2(x) =1, divide both sides by 3

u^2 = \frac{1}{3}

Take square root on both sides

u = +-\frac{1}{\sqrt{3} }

We replace tan(x) for 'u'

tan(x) = +-\frac{1}{\sqrt{3} }  

x = 30 because tan(30) =+\frac{1}{\sqrt{3} }  in first quadrant

      x = 30      (tan is positive in first quadrant)

tan(x) =-\frac{1}{\sqrt{3} }                                                    

  x = 150 because tan(150) =-\frac{1}{\sqrt{3} }  in second quadrant

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4 0
3 years ago
Plzzzzz help me with this
ehidna [41]

Answer:

We conclude that we must add 4² or 16 to complete the square.

Hence, option C i.e. 16 is the correct answer.

Step-by-step explanation:

We know that the perfect square formula is

<em>(a + b)² = a² + b² + 2ab</em>

Given the equation

x^2+8x

Let us add 4² or 16 in the equation

x^2+8x+4^2

x^2+\:2\left(1\right)\left(4\right)x+4^2

as <em>(a + b)² = a² + b² + 2ab, </em>so

<em />x^2+8x+4^2=\left(x+4\right)^2<em />

<em />

Therefore, we conclude that we must add 4² or 16 to complete the square.

Hence, option C i.e. 16 is the correct answer.

4 0
3 years ago
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EleoNora [17]
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2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
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From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
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castortr0y [4]

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