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meriva
3 years ago
12

Hi i need help with something, tysm

Mathematics
1 answer:
mylen [45]3 years ago
8 0

Answer:

Step-by-step explanation:

y=-3/2x+5

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18 – 12 + x = 10 What value of x makes the equation true? * explanation plz
Kay [80]

Answer:

x = 4

Step-by-step explanation:

Solve for x:

x - 12 + 18 = 10

Hint: | Group like terms in x - 12 + 18.

Grouping like terms, x - 12 + 18 = x + (18 - 12):

x + (18 - 12) = 10

Hint: | Evaluate 18 - 12.

18 - 12 = 6:

x + 6 = 10

Hint: | Isolate terms with x to the left hand side.

Subtract 6 from both sides:

x + (6 - 6) = 10 - 6

Hint: | Look for the difference of two identical terms.

6 - 6 = 0:

x = 10 - 6

Hint: | Evaluate 10 - 6.

10 - 6 = 4:

Answer: x = 4

7 0
3 years ago
Read 2 more answers
For the polynomial f(x) = 3x^3 + 3x^2 - 13x + 12 determine the average rate of change between the two given values for x
AnnyKZ [126]

Answer:

Well plz dont delete my question  I need points to get mine out

Step-by-step explanation:

4 0
3 years ago
Marco draws a card and replaces it 10 times from a standard deck of 52 cards. He draws 8 red cards and 2 black cards. What is th
Andreas93 [3]
4/5 chance is the answer to that
3 0
3 years ago
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Find the equation of a line passing through the points (2,6) and (-2,-10)
navik [9.2K]

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-10-6}{-2-2}\implies \cfrac{-16}{-4}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=4(x-2) \\\\\\ y-6=4x-8\implies y=4x-2

5 0
3 years ago
Read 2 more answers
The number 64 has the property that it is divisible by its units digit. How many whole numbers between 10 and 50 have this prope
sineoko [7]

Answer:

\large \boxed{17}

Step-by-step explanation:

Let's call the numbers "<em>tu</em>", where<em> t</em> is the tens digit and <em>u</em> is the units digit.

We can solve this by the "brute force" method —  examining each number to see if it satisfies the conditions.

\begin{array}{cccl}\mathbf{u}&\mathbf{tu}& \textbf{Divisible by u} & \\0 &20, 30, 40 & 0 & \text{Division by zero is impossible}\\1 & 11, 21, 31, 41 & 4& \text{All numbers are divisible by one}\\2 & 12, 22, 32, 42 & 4 & \text{All even numbers are divisible by two}\\3 & 13,  23, 33, 43 & 1 &\text{Only 33 is divisible by three}\\4 & 14, 24, 34, 44 & 2 & \text{Only 24 and 44 are divisible by four}\\5 & 15, 25, 35, 45 & 4 & \text{Numbers ending in 5 are divisible by five}\\\end{array}

\begin{array}{cccl}6 & 16, 26, 36, 46 & 1 & \text{Only 36 is divisible by six}\\7 & 17, 27, 37, 47 & 0 & \text{None of the numbers is divisible by seven}\\8 & 18, 28, 38, 48 & 1 & \text{Only 48 is divisible by eight}\\9 & 19, 29, 39, 49 & 0 & \text{None of the numbers is divisible by nine}\\& \textbf{TOTAL =} &\mathbf{17}& \\\end{array}\\\text{$\large \boxed{\mathbf{17}}$ numbers between 10 and 50 are divisible by their units digit}

5 0
3 years ago
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