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1 year ago

5

the map is drawn to the scale of 1:4000 and the distance in between two places on the map is 4 cm what is the actual distance be

tween those two places

1 answer:

mafiozo [28]1 year ago

4 0

Answer:

4 × 4000 = 16000cm or 160 meters

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Find the equation is standard form, of the line passing through he points (2,-3) and (4,2)

Simora [160]

The point slope formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

$(2,\ -3)\to x_1=2,\ y_1=-3\\(4,\ 2)\to x_2=4,\ y_2=2$

Substitute:

$m=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}=2.5\\\\y-(-3)=2.5(x-2)\\\\y+3=2.5x-5\ \ \ \ |+5\\\\y+8=2.5x\ \ \ \ \ \ |-y\\\\2.5x-y=8\ \ \ \ \ |\cdot2\\\\\boxed{5x-2y=16}$

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3 years ago

Brianna answered 80% of the questions correct on her math test. Which fraction represents the number of questions she answered c

LiRa [457]

Answer: 4/5

Step-by-step explanation:

80% is 80/100

80/100 simplified is 4/5

7 0

3 years ago

Read 2 more answers

Write out the sample space for the given experiment. Use the following letters to indicate each choice: M for mushrooms, A for a

MrMuchimi

Answer: {(MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)}

Step-by-step explanation:

Sample space is a set that contains all the possible outcomes for an event.

For salad:

Choices for extra toppings (mushrooms, olives) =2

Choices for meats (bacon, eggs) =2

Choices for dressings (vinaigrette, honey mustard.)= 2

By Fundamental counting principal .

The number of different salads can be made= (Choices for extra toppings) x (Choices for meats ) x (Choices for dressings)

= 2 x 2 x 2 = 8

All the possible outcomes = (MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)

Required Sample space would be : {(MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)}

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2 years ago

If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n

bearhunter [10]

Let $x$ be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is $x+4039,$ so our answer is $\boxed{4039}.$

For completeness, though, let's solve for the value of $x$ that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term $a_1,$ last term $a_n,$ and $n$ terms, is $\frac{n(a_1+a_n)}{2}.$ Plugging in our known values gives us the equation $\frac{4040(2x+4039)}{2}=2020,$ which simplifies to $2x+4039=1.$ Thus, $x=-2019,$ so the 4040 consecutive integers are $-2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020.$ Notice how everything except the $2020$ cancels out!

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3 years ago

PLEASE HELP! FUNCTIONS

satela [25.4K]

Answer: 7

Step-by-step explanation:

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3 years ago