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Lina20 [59]
3 years ago
11

34,258 and 47,163 The value of 4 in------ is ----- times The value of 4 in -------

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0
The value of 4 in 47,163 is 10 times greater than the value of 4 in 34,258.

Each time you move one place over (e.g. tens to hundreds) the number gets 10 times larger if you move to the left and 10 times smaller if you move to the right. So, for example you go from tens to hundreds it is 10 times larger, but if you go from hundreds to tens then it is 10 times smaller.
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Yearly tuition, housing, and fees for a local college are $9500, $1500, and $1870 respectively. You have saved $6100 and have a
Korvikt [17]
You will need $4270 more

(9500+1500+1870)-(6100+2500)
12870-8600
4270
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3 years ago
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Jayden leans a 30-foot ladder against a wall so that it forms an angle of 65 ∘ with the ground. How high up the wall does the la
vaieri [72.5K]

Answer:

27.19 ft.

Step-by-step explanation:

sin 65 = x/30

sin 65(30) = x

27.189 ≈27.19

8 0
3 years ago
2/5 of 2/3
Vilka [71]

Answer:

4/15 is your answer my friend

Step-by-step explanation:

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2 years ago
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How do I find the slope of the line through (–9, –10) and (–2, –5)?
storchak [24]
Answer:
slope of line is 5/7

Explanation:
The slope of the line can be calculated using the following rule:
slope = \frac{y2-y1}{x2-x1}

The given points are:
(-9,-10) which represent (x1,y1)
(-2,-5) which represent (x2,y2)

Substitute with the points in the above equation to get the slope as follows:
slope = \frac{-5-(-10)}{-2-(-9)} = 5/7

Hope this helps :)

4 0
3 years ago
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The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
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