Answer:
y-1 = 5(x+8)
Step-by-step explanation:
The standard equation of a line in point slope form is expressed as;
y-y0 = m(x-x0)
m is the slope
(x0, y0) is the point
Given
Slope m = 5 (assumed value)
Point (-8,1)
Substitute the given data's into the formula
y -1 = 5(x-(-8))
y-1 = 5(x+8)
Hence the required equation is y-1 = 5(x+8)
Answer:
The proposed equation is solved as follows:
2X + 7 = 21
2X = 21 - 7
2X = 14
X = 14 / 2
X = 7
The value of X is 7.
A first degree equation is an algebraic equation in which each term is either a constant or a product of a fixed term on a single variable. Therefore, this equation is a first degree one, since it only has a single variable, which is X.
Answer:
F = 110°
I'm not sure, but since no one answered, here it goes...
Step-by-step explanation:
∵ FD = FE (Given in Diagram)
∴ ΔDFE is isosceles , ∴m∠E = m∠D
1 ) 3x + 14 = 5x
14 = 5x - 3x
14 = 2x
14 / 2 = x
7 = x
m∠E = 3*7 + 14 = 35°
m∠D = 5*7 = 35°
m∠F = 180 - (35+35)
m∠F = 110°
Answer:
57cm²
Step-by-step explanation:
area for trapezoid=
b¹+b²=x
x÷2=v
v×h=z
h=height
b=base
14+5=19
19÷2=9.5
9.5×6=57
