Question

Multiply Conjugates Using the Product of Conjugates Pattern

Answer 1

Answer:

The product is the difference of squares is $\left(9c+5\right)\left(9c-5\right)=81{{c}^2}-25$

Step-by-step explanation:

Explanation

• The given expression is (9 c+5)(9 c-5).

• We have to multiply the given expression.
• Square the first term 9c. Square the last term 5 .

$\begin{aligned}&(9 c+5)(9 c-5)=(9 c)^{2}-(5)^{2} \\&(9 c+5)(9 c-5)=81 c^{2}-25\end{aligned}$