3 years ago

How do you simplify 6/8

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

6/8 would be simplified by to so, 6/8 = 3/4

Nadusha1986 [10]3 years ago

8 0

6/8

Divide 2 from numerator and denominator

3/4 is your answer

Hope this helps

You might be interested in

Define the polynomial by the number of terms.

Lera25 [3.4K]

If the number of terms is one then it is called a mono-nomial
if number of terms is two then it is called binomial.
if the number of terms is three or more than three then it is called poly-nomial.

3 0

3 years ago

How to show these 2 problems are inverses

nataly862011 [7]

$\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x$

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other

8 0

2 years ago

Checking my work. which one?

Genrish500 [490]

Answer:

Dividing exponents you subtract.

3^8/3^5 = 3^3

3^3

Multiplying exponents when an exponent is raised to another.

(3^3)^3 = <u>3^9</u>