All categories

2 years ago

How many grams of Ag2S2O3 form

1 answer:

4 0

Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgBr: 2 moles
Na₂S₂O₃: 1 mole
Ag₂S₂O₃: 1 mole
NaBr: 2 moles

The molar mass of the compounds is:

AgBr: 187.77 g/mole
Na₂S₂O₃: 158 g/mole
Ag₂S₂O₃: 327.74 g/mole
NaBr: 102.9 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

AgBr: 2 moles ×187.77 g/mole= 375.54 grams
Na₂S₂O₃: 1 mole ×158 g/mole= 158 grams
Ag₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 grams
NaBr: 2 moles ×102.9 g/mole= 205.8 grams

<h3>Mass of Ag₂S₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?

$mass of Ag_{2} S_{2} O_{3} =\frac{125 grams of AgBrx327.74 grams of Ag_{2} S_{2} O_{3}}{375.54 grams of AgBr}$

<u><em>mass of Ag₂S₂O₃= 109.09 grams</em></u>

Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

You might be interested in

How is hess's law applied in calculating enthalpy

eimsori [14]

Answer:Hess's law states that the change of enthalpy in a chemical reaction (i.e. the heat of reaction at constant pressure) is independent of the pathway between the initial and final states. ... Hess's law allows the enthalpy change (ΔH) for a reaction to be calculated even when it cannot be measured directly.

Explanation:

3 0

3 years ago

Read 2 more answers

The atomic number of Oxygen is 8. Therefore, which of the following answers would correspond to what would be in the nucleus of

melomori [17]

Answer:

Its official chemical symbol is O, and its atomic number is 8, which means that an oxygen atom has eight protons in its nucleus. ... Oxygen is normally found as a

5 0

2 years ago

The equation for another reaction used in industry isCO(g) + H₂O(g) <img src="https://tex.z-dn.net/?f=%5Crightleftharpoons" id="

Sloan [31]

Answer:

(i) CO = 0.4 mol; H₂O = 1.6 mol; Kc = 4

(ii) CO = 0.67 mol; H₂O = 0.67 mol; CO₂ = 1.33 mol; H₂ = 1.33 mol

Explanation:

(i) For the equation given let's make a table of the concentrations for equilibrium (the volume is constant, so, we can do it with moles number)

CO(g) + H₂O(g) ⇄ H₂(g) + CO₂(g)

2.0 mol 3.2 mol 0 0 <em>Initial</em>

-x -x +x +x <em>Reacts</em> (stoichiometry is 1: 1: 1: 1)

2.0-x 3.2-x x x <em>Equilibrium</em>

In the equilibrum, the moles number of hydrogen and carbon dioxide are 1.6 mol, so x = 1.6 mol

The amounts of CO and H₂O are:

CO = 2.0 - 1.6 = 0.4 mol

H₂O = 3.2 - 1.6 = 1.6 mol

The constant of the equilibrium is the multiplications of the concentrations of products divided by the multiplication of the concentration of the reactants (all the concentrations elevated to the coefficient). So:

Kc = (1.6x1.6)/(0.4x1.6)

Kc = 1.6/0.4

Kc = 4

(ii) Kc must remais constant (it only changes with the temperature), so let's construct a new table of equilibrium:

CO(g) + H₂O(g) ⇄ H₂(g) + CO₂(g)

2.0 mol 2.0 mol 0 0 <em>Initial</em>

-x -x +x +x <em>Reacts</em> (stoichiometry is 1: 1: 1: 1)

2.0-x 2.0-x x x <em>Equilibrium</em>

Kc = (x*x)/((2.0-x)*(2.0-x))

4 = x²/(4 - 4x + x²)

16 - 16x + 4x² = x²

3x² - 16x + 16 = 0

Using Baskhara's equation:

Δ =(-16)² - 4x3x16

Δ = 256 - 192

Δ = 64

x = (-(-16) +/- √64)/(2*3)

x' = (16 + 8)/6 = 4

x'' = (16 - 8)/6 = 1.33

x must be small than 2.0, so x = 1.33 mol, which is the amount of hydrogen and carbon dioxide at equilibrium. The both reactants has 2.0 - 1.33 = 0.67 mol at equilibrium.

5 0

3 years ago

Out of the given four mixtures, the one that appears clear and transparent is:

natita [175]

Answer:

d) Sugar and water

Explanation:

The sugar and water solution will have a clear and transparent outlook.

When we look at a solution of a mixture of sugar and water, it a homogenous one.

A homogenous solution have their solution in one phase.

The solute is sugar and the solvent is water.

The solution obtained is colorless therefore, light will pass through without any obstruction.

The other solutions will be translucent or opaque

4 0

3 years ago

Which of the following is true about the behavior of an organism?

Semmy [17]

Answer:

C. The behavior of an organism is not influenced by either its heredity or its environment.

4 0

3 years ago