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jasenka [17]
3 years ago
12

Dry ice sublimes into carbon dioxide gas. If the proper conditions are maintained and the system is closed, the dry ice and the

carbon dioxide gas will eventually.
Chemistry
1 answer:
Shalnov [3]3 years ago
8 0

Dry ice sublimes into carbon dioxide gas. If the proper conditions are maintained and the system is closed, the dry ice and the carbon dioxide gas will eventually.

1 )become the same phase

2) reach equilibrium

3)same properties and composition  throughout

4) both become same phase and reach equilibrium

Answer:

Under the the proper conditions  maintained over the closed system , the dry ice and the carbon dioxide gas will eventually reach equilibrium.

Explanation:

The reactions which do not go on completion and in which the reactant forms product and the products goes back to the reactants simultaneously are known as equilibrium reactions.

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.

For a chemical equilibrium reaction, equilibrium state is achieved when the rate of forward reaction becomes equals to rate of the backward reaction.

Under the the proper conditions  maintained over the closed system , the dry ice and the carbon dioxide gas will eventually reach equilibrium.

CO_2(s)\rightleftharpoons CO_2(g)

Amount of carbon dioxide changing from solid to gas will be equal to amount of carbon dioxide changing from gas to solid.

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No it stays the same the only thing that changes are the number of electrons
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How would you make a 2.00L of 0. 500M sodium chloride solution. (assume you have a fully equipped lab with water); sketch, calc
Gwar [14]

Answer:

Sodium chloride solution:

First you need to calculate the mass of salt needed (done in the explanation), which is 58.44g. Then it have to be weighted in an analytical balance in a weighting boat and then transferred into a 2L volumetric flask that is going to be filled until the mark with distilled water.

Sulfuric acid dilution:

First you need to calculate the volume needed (done in the explanation), it is 16.6 mL. Using a graduated pipette one measures this volume and transfer it into a 2L volumetric flask that is already half filled with distilled water, and then one fills it until its mark.

Explanation:

Sodium chloride solution:

Each liter of a 0.500M solution has half mol, so 2L of said solution has 1 mol of salt. Sodium chloride molar mass is 58.44g/mol, so in 2L of solution there is 58.44g of salt. That`s the mass that`s going to be weighted and transferred to a 2L volumetric flask.

Sulfuric acid dilution:

This is the equation for dilution of solutions:

c_{1} v_{1} =c_{2} v_{2}

Where "c1" stands for the initial concentration (stock solution concentration), "v1" for the initial volume (volume of stock solution used), "c2" for the desired concentration and "v2" for the desired volume.

When we are diluting from a stock solution we want to know how much do we have to pipette from the stock solution into our volumetric flask. We do so by isolating the "v1" term from the dilution equation:

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5 0
3 years ago
A sample of a gas at room temperature occupies a volume of 29.0 L at a pressure of 562 torr . If the pressure changes to 2810 to
UkoKoshka [18]

Answer:

The new volume will be 5.80 L

Explanation:

Step 1: Data given

The initial volume = 29.0 L

The initial pressure = 562 torr = 562 /760 atm = 0.739474 atm

The pressure changes to 2810 torr = 2810 /760 atm = 3.697368 atm

The temperature and number of moles will not change

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒With P1 = the initial pressure = 0.739474 atm

⇒with V1 = the initial volume = 29.0 L

⇒with P2 = the increased pressure = 3.697368 atm

⇒with V2 = The new volume = TO BE DETERMINED

0.739474 atm * 29.0 L = 3.697368 atm * V2

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OR

562 torr * 29.0 L = 2810 torr * V2

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