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jasenka [17]
2 years ago
12

Dry ice sublimes into carbon dioxide gas. If the proper conditions are maintained and the system is closed, the dry ice and the

carbon dioxide gas will eventually.
Chemistry
1 answer:
Shalnov [3]2 years ago
8 0

Dry ice sublimes into carbon dioxide gas. If the proper conditions are maintained and the system is closed, the dry ice and the carbon dioxide gas will eventually.

1 )become the same phase

2) reach equilibrium

3)same properties and composition  throughout

4) both become same phase and reach equilibrium

Answer:

Under the the proper conditions  maintained over the closed system , the dry ice and the carbon dioxide gas will eventually reach equilibrium.

Explanation:

The reactions which do not go on completion and in which the reactant forms product and the products goes back to the reactants simultaneously are known as equilibrium reactions.

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.

For a chemical equilibrium reaction, equilibrium state is achieved when the rate of forward reaction becomes equals to rate of the backward reaction.

Under the the proper conditions  maintained over the closed system , the dry ice and the carbon dioxide gas will eventually reach equilibrium.

CO_2(s)\rightleftharpoons CO_2(g)

Amount of carbon dioxide changing from solid to gas will be equal to amount of carbon dioxide changing from gas to solid.

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2 years ago
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The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
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Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

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(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

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\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

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