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2 years ago

6

If the endpoints of ST are S (1,4) and T (5,2) then the midpoint is in Quadrant IV?

1 answer:

irina [24]2 years ago

6 0

It is false that the midpoint is in quadrant IV

<h3>How to determine the midpoint location?</h3>

The endpoints are given as:

S (1,4) and T (5,2

The midpoint is

(x, y) = 0.5 *(x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 *(1 + 5, 4 + 2)

Evaluate the expression

(x, y) = (3, 3)

The point (3, 3) is located in the first quadrant

Hence, it is false that the midpoint is in quadrant IV

Read more about quadrants at:

brainly.com/question/7196312

#SPJ1

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2-(-2x-4)=3x+6-x what is the answer to that?

ruslelena [56]

98--8=

Step-by-step explanation:

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3 years ago

(Round to the nearest tenth of a percent.) In 2011, the IRS increased the deductible mileage cost to

RUDIKE [14]

Answer:

$\%Change = 8.8\%$

Step-by-step explanation:

Given

$Initial = 51\ cents$

$Final = 55.5\ cents$

Required

Determine the percentage change

Percentage change is calculated as;

$\%Change = \frac{Final - Initial}{Initial} * 100\%$

$\%Change = \frac{55.5 - 51 }{51 } * 100\%$

$\%Change = \frac{4.5}{51} * 100\%$

$\%Change = \frac{4.5* 100\%}{51}$

$\%Change = \frac{450\%}{51}$

$\%Change = 8.8\%$

<em>Hence, the percentage change is approximately 8.8%</em>

6 0

2 years ago

a positive integer is twice another. The sum of the reciprocals of the two positive integers is frac 3/16, find the two integers

gizmo_the_mogwai [7]

Step-by-step explanation:

Let $x$ be the smallest integer

Let $2x$ be the larger integer

As the sum of the reciprocals of the two positive integers is frac 3/16

So,

$\frac{1}{x}\:+\:\frac{1}{2x}\:=\:\frac{3}{16}$

$\mathrm{Multiply\:by\:LCM=}16x$

$\frac{1}{x}\cdot \:16x+\frac{1}{2x}\cdot \:16x=\frac{3}{16}\cdot \:16x$

Simplify

$24=3x$

$\mathrm{Switch\:sides}$

$3x=24$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3x}{3}=\frac{24}{3}$

$x=8$

So,

$2x=16$

<h2>Verification:</h2>

$\frac{1}{8}\:+\:\frac{1}{16}$

$\mathrm{Least\:Common\:Multiplier\:of\:}8,\:16:\quad 16$

$=\frac{2}{16}+\frac{1}{16}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{2+1}{16}$

$=\frac{3}{16}$

Therefore,

$\frac{1}{8}+\frac{1}{16}=\frac{3}{16}$

Keywords: word problem , integer

Learn more about solving integer word problem from brainly.com/question/10905225

#learnwithBrainly

4 0

3 years ago

What fraction must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions

DanielleElmas [232]

Answer:

so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.

Step-by-step explanation:

let the fraction be x

(1/4 + 1/6)-x = 1/12

or, 10/24 - x = 1/12

or, 5/12-1/12 = x

so, x = 4/12 = 1/3

8 0

2 years ago

Simplify:<br>4z+3/15+8q+2/15+6z-4q

Liono4ka [1.6K]

The answer would be 10z+1/3+4q

7 0

3 years ago