Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
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How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
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Answer:
So then the difference between the two proportions is 0.045 and if we convert this into % we got
Step-by-step explanation:
For this case we can define the following notation:
represent the unemployment rate for high school graduates with no college degree
represent the unemployment rate for college graduates with a bachelor's degree
And for this case we need to find the difference in proportions of those unemployed between these two groups, we want to find:
From the info given we have 
And the difference:
So then the difference between the two proportions is 0.045 and if we convert this into % we got
I can help you but what is the operation of math
Selection B is appropriate.
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It takes 12 times as long to fill the whole tank as it does to fill 1/12 of the tank.
.. 12 * (1/3 hour) = (1/3)*12 hour
Answer:
top left
Step-by-step explanation:
