Solution set of inequality-7<3x+2<11, where x is a real number
Answer: (x,y)=(14/4,0)
Step-by-step explanation:
y=-2(x-3)(2)+2
Clear the brackets
y=-2(2x-6)+2
y=-4x+12+2
y=-4x+14
To get the x-intercept y=0
0=-4x+14
4x=14
x=14/4
(x,y)=(14/4,0)
Y = x + 5....so we sub in x + 5 for y in the other equation
4x + y = 20
4x + x + 5 = 20
5x + 5 = 20
5x = 20 - 5
5x = 15
x = 15/5
x = 3
y = x + 5
y = 3 + 5
y = 8
solution is (3,8)
X = jane, y = jasmine, z = jocelyn
x + y + z = 56
x = 3z
y = 2z + 2
3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn
x = 3z
x = 3(9)
x = 27 <=== jane
y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
Answer:
58 attendees
Step-by-step explanation:
Find the unit rate
cost $392 if it has 28 attendees
392/28 = $14 per attendee
How many attendees can there be,if the budget is $812?
812/14 = 58 attendees
