3 years ago

What is the largest possible value x could take given that it must be an integer? x < 5

Mathematics

1 answer:

salantis [7]3 years ago

5 0

Answer:

Step-by-step explanation:

No greater number than 4 can be x because otherwise it'll be equal to or more than 5

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1 ln(1) + 2 ln(2) + 3 ln(3) + ⋯ + 10 ln(10)

Lapatulllka [165]

Answer:

$\ln(1\cdot2^{2} \cdot3^{3}\cdot4^{4} ...\cdot10^{10} )$

Step-by-step explanation:

By logarithm rules

$\ln1+2\ln2+3\ln3+....+10\ln10\\\ln1+\ln2^2+\ln3^3+....\ln10^{10}\\\ln(1\cdot2^{2} \cdot3^{3}\cdot4^{4} ...\cdot10^{10} )$

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3 years ago

Can u please help me

Alchen [17]

Answer:

that answer u put is correct and r u in K12 to lol

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2 years ago

Solve: the quantity 3x minus 15 divided by 2 = 4x

Anon25 [30]

Answer:

x=-3

Step-by-step explanation:

(3x-15)/2 = 4x

Multiply each side by 2

(3x-15)/2 *2= 4x*2

3x-15 = 8x

Subtract 3x from each side

3x-15-3x = 8x-3x

-15 = 5x

Divide each side by 5

-15/5 = 5x/5

-3 =x

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2 years ago

2 x y`- 3 y=0

riadik2000 [5.3K]

Answer:

2xy-3y=0

y(2x-3) =0

2x-3=0

2x=3

x=3/2

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2 years ago

4x−4<8 AND 9x+5>23 Solve for X.

siniylev [52]

Hope this will help u...☝✌✌✌✌

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2 years ago