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butalik [34]
3 years ago
5

The ratio of seventh graders to sixth graders on a chess team is 5 to 3. What is the ratio of seventh graders to total chess pla

yers?
Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

5:8

Step-by-step explanation:

We don't know how much is the total, so 5:5+3

Seventh graders to total is 5:8

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I need help with this practice problem It’s from my trig prep guide
Zinaida [17]

We know that π = 180°, therefore:

1.

2\pi=2(180)=360

Answer: correct

2.

\frac{5\pi}{6}=\frac{5(180)}{6}=\frac{900}{6}=150

Answer: no correct

3.

\frac{\pi}{6}=\frac{180}{6}=30

Answer: no correct

4.

\frac{5\pi}{4}=\frac{5(180)}{4}=\frac{900}{4}=225

Answer: correct

5.

\frac{4\pi}{3}=\frac{4(180)}{3}=\frac{720}{3}=240

Answer: correct

6 0
1 year ago
ABCD is a parallelogram. Segment AC = 4x + 10. Find the value of x and y.
valkas [14]

Answer:

The values of x and y in the diagonals of the parallelogram are x=0 and y=5

Step-by-step explanation:

Given that ABCD is a parallelogram

And segment AC=4x+10

From the figure we have the diagonals AC=3x+y and BD=2x+y

By the property of parallelogram the diagonals are congruent

∴ we can equate the diagonals AC=BD

That is 3x+y=2x+y

3x+y-(2x+y)=2x+y-(2x+y)

3x+y-2x-y=2x+y-2x-y

x+0=0 ( by adding the like terms )

∴ x=0

Given that segment AC=4x+10

Substitute x=0  we have AC=4(0)+10

=0+10

=10

∴ AC=10

Now (3x+y)+(2x+y)=10

5x+2y=10

Substitute x=0, 5(0)+2y=10

2y=10

y=\frac{10}{2}

∴ y=5

∴ the values of x and y are x=0 and y=5

5 0
4 years ago
Need help <br> Correct answers only.
disa [49]

The diameter of the circle is the same as the side length of the bounding square. The radius of the circle is 8 in, so the side length of the square is 16 in.

Then the area between the square and circle is obtained by subtracting the area of the circle from the area of the square:

A_{\rm circle}=\pi(8\,\mathrm{in})^2=64\pi\,\mathrm{in}^2

A_{\rm square}=(16\,\mathrm {in})^2=256\,\mathrm{in}^2

and the area you want is

256-64\pi\,\mathrm{in}^2\approx54.9\,\mathrm{in}^2

6 0
4 years ago
Which shows the correct substitution of the values a, b, and c from the equation -2=-x+x^2-4 into the quadratic formula?
Greeley [361]
Given the equation:

(1) -2=-x+ x^{2}-4

We need to find a, b and c. So, we know that a quadratic equation is given by:

(2) ax^{2}+bx+c=0

Then, we need to order the equation (1) and to adjust it to the equation (2), so:

x^{2}-x-2=0

So, if we compare these two equations, the conclusion is:

a=1
b=-1
c=-2

(3) x= \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

Substituiting a, b and c into (3):

x= \frac{-(-1)\pm \sqrt{(-1)^{2}-4(1)(-2)}}{2(1)}

Finally, the results are two values:

x_{1}=2
x_{2}=-1

7 0
3 years ago
Read 2 more answers
Help meh pleaseeeeeeee
KengaRu [80]

Answer:

see below

Step-by-step explanation:

for the explanation for the exercise

AT LEAST 35 minutes per day

t ≥ 35 minutes

for the second one

you need to be NOT LESS THAN 56 inches

but you can be 56 inches

h ≥ 56 inches

4 0
2 years ago
Read 2 more answers
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