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2 years ago

Brian saved $8 on a pair of sneakers with a 25% coupon at Kohls

Mathematics

1 answer:

Scilla [17]2 years ago

8 0

Answer: 32$

Step-by-step explanation: 8 x 4 = 32

32 divided by 4 = 8

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The intercept (factored) form a parabola.

Svet_ta [14]

The a value affects the graph by vertically stretching or compressing the graph.
The r and s values affect the zeros, or x intercepts of the parabola, and therefore the vertex.
Hope this helps!

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2 years ago

sleet_krkn [62]

Division , timetable , adding , and subtracting

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3 years ago

2/3 - 5/6 - 7/9 = simplifying

ch4aika [34]

Answer:

-17/18

Step-by-step explanation:

find least common multiple, which is 18

multiply the numerators by the number you multiplied on the denominator.

and subtract.

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2 years ago

The sum of two numbers is 25. One of the numbers is fifteen less than the other. Find the numbers.

bija089 [108]

20+5 because 5 is 15 less than 25.

4 0

3 years ago

Read 2 more answers

A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the

Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the width W as such

$W = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that $\sigma^{2} = 9$ , then $\sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3$ . So

$W = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.96*\frac{3}{\sqrt{n}}$

$\sqrt{n} = 1.96*3$

$(\sqrt{n})^2 = (1.96*3)^{2}$

$n = 34.57$

Rounding up

A sample size of 35 is needed.

3 0

2 years ago