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alexgriva [62]
2 years ago
12

Tomas borrowed money from his grandmother. to pay back the loan, he gives her the same amount of money each month. the linear fu

nction that models the amount of money ,y, in dollars that Tomas still owes his grandmother based on the number of months,x,since he borrowed the money is represented by y=1500-35x​
Mathematics
2 answers:
kicyunya [14]2 years ago
3 0

Answer:

Step-by-step explanation:

neonofarm [45]2 years ago
3 0

Answer:

Step-by-step explanation:

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Joe determined the mass of 2 boxes using a scale. Since the cost of each box is the same, Joe would like to choose the box with
Naddika [18.5K]

Answer:

32.012 kg < 32.02 kg

Step-by-step explanation:

32.012 kg < 32.02 kg

7 0
3 years ago
Which expression is a prime polynomial?
irakobra [83]

The expression that is a prime polynomial is:

B. x^3 - 27y^2.

<h3>What is a prime polynomial?</h3>

A prime polynomial is a polynomial that cannot be factored.

In this problem, item b gives a prime polynomial, as:

  • In item a, 3 is a common factor, hence the polynomial can be factored.
  • In item c, x is a common factor, hence the polynomial can be factored.
  • In item d, the polynomial can be factored according to it's roots.

More can be learned about prime polynomials at brainly.com/question/26388060

#SPJ1

4 0
2 years ago
The value of n in the inequality 3n + 1 &lt; 7 is
aliya0001 [1]

3n + 1 < 7

Solve:

3n < 6

n < 2

The answer is C.

8 0
3 years ago
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad &#10;\begin{cases}&#10;63=3\cdot 3\cdot 7\\&#10;6=2\cdot 3&#10;\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\&#10;\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
PLEASE! PLEASE HELP ME!!!!
Nataliya [291]

Answer:

c and d

Step-by-step explanation:

ok so i do not know how to explain

5 0
3 years ago
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