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Alexxandr [17]
2 years ago
11

A trash can is in the shape of a cylinder. It has a radius of 2 feet and a height of 5 feet. What is the volume of the trash can

? Round to the nearest tenth. Use 3.14 for pi
Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
6 0

Answer: 62.8 cubic feet

Step-by-step explanation:

R is radius

H is height

R=2ft

H=5ft

V=(3.14)(2)^2(5)

V=62.8 cubic feet

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A.) 61<br> B.) 48.8<br> C.) 39
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Answer:

C

Step-by-step explanation:

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Angiogenesis is the first one

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4 years ago
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
2 years ago
Question 2. Do I divide 9.76 by 8 or the opposite?
schepotkina [342]
It could go either way
7 0
3 years ago
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Simplify x to the 1/3 power (x to the 1/2 power + 2x to the 2 power )
OverLord2011 [107]

Answer:

x^(5/6) + 4(x^(7/3))


Step-by-step explanation:

Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )


Simplify x^(1/3) × (x^(1/2) + (2x)^2)

= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)

= x^(1/3+1/2) + 4(x^(1/3+2))

= x^(5/6) + 4(x^(7/3))


x^(1/3) is y such that y^3 = x

(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x


x^(1/2) = √2 = y such that y^2 = x

(2x)^2 = 4x^2






6 0
3 years ago
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