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maks197457 [2]
1 year ago
15

Please help me im in a rush

Mathematics
1 answer:
Trava [24]1 year ago
3 0

Answer:

\frac{x}{y}  =  \frac{10}{5}   \\  =  \frac{5}{1}

1. •°• y is 5 times x

\frac{x}{y}  =  \frac{30}{5}  \\  =  \frac{6}{1}

2. •°• y is 6 times x

\frac{x}{y}  =  \frac{56}{8}  \\  =  \frac{7}{1}

3. •°• y is 7 times x

\frac{x}{y}  =  \frac{88}{11}  \\  =  \frac{8}{1}

4. •°• y is 8 times x

2 \times \frac{7}{4}

•°• y is 2 times x

5 \times \frac{7}{4}

•°• y is 5 times x

8 \times \frac{7}{4}

•°• y is 8 times x

11 \times \frac{7}{4}

•°• y is 11 times x

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I think it’s C because I did have this question but I’m not sure
5 0
3 years ago
Identify the inequality that represents the following problem "Two more than three times a number is at least eight" What is the
lesantik [10]

The right answer is Option C.

Step-by-step explanation:

Given word problem is;

Two more than three times a number is at least eight

Let,

n be the number.

Times a number = 3n

Two more means addition;

Two more than three times a number = 3n+2

At least eight means that it can either be 8 or more.

Therefore,

3n+2≥8 is the solution set.

The right answer is Option c.

Keywords: linear inequality, solution set

Learn more about linear inequalities at:

  • brainly.com/question/13101704
  • brainly.com/question/13113987

#LearnwithBrainly

5 0
3 years ago
The value given below is discrete. Use the continuity correction and describe the region of the normal distribution that corresp
lions [1.4K]

Answer:

D. The area to the left of 7.5

Step-by-step explanation:

If fewer than 8 passengers do not show up for a flight, then at most 7 passengers do not show up for a flight. Therefore, applying continuity correction, the area under the curve must comprehend from zero to seven passengers not showing up, but not the 8th passenger. Thus, the area must be to the left of 7.5.

The answer is D. The area to the left of 7.5.

6 0
2 years ago
Find the zeros of the function and state their multiplicities. y=x^4-8x^2+16
Volgvan
   
y=0\\\\ 
x^4-8x^2+16 = 0\\\\
(x^2)^2 - 2\cdot 4 \cdot x^2 + 4^2 = 0\\\\
(x^2 - 4)^2 = 0\\\\
(x^2 - 4)(x^2 - 4)=0\\\\
(x-2)(x+2) (x-2)(x+2) = 0\\\\
(x-2)(x-2) (x+2)(x+2) = 0\\\\
\Longrightarrow~~~ x_1 = 2;~x_2 = 2;~ x_3= -2;~x_4 = -2\\\\
\text{Conclusion:}\\\\
x_1 = x_2 = 2~~~   \text{double root}\\\\
x_3 = x_4 = -2~~~   \text{double root}\\\\




7 0
2 years ago
Can some one double check this for me?
Marina86 [1]

Answer:

Yep everything is correct!

You jsut multiply the beginning value with out the “0”

And then after that for every zero you see from 10-10000 just add the amount of “0”s.

5 0
2 years ago
Read 2 more answers
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