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3 years ago

Find the slope using points (2, 2) and (-5, 4)

Mathematics

1 answer:

lapo4ka [179]3 years ago

7 0

-2/7.... the formula is y2-y1/x2-x1

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Carlos graphs the equations y = 0.5x2 + 3 and y = –4x2 + 24x – 35 and generates the graph below. Which conclusion is supported b

never [62]

Answer:

It has no solution

Step-by-step explanation:

Here we have to draw the graph of y = 0.5x^2 + 3 and y = -4x^2 + 24x - 35.

I have attached the graph of these two functions.

Since the graphs of the functions didn't cut each other.

Therefore, answer is "it has no solution."

Hope this will helpful.

Thank you.

3 0

3 years ago

Read 2 more answers

Find the slope of the line through each pair of points

ddd [48]

The answer is 27/23. The way you listed the answers is confusing so I’m not giving a letter. Because [17+10]/[17+6]= 27/23

5 0

3 years ago

Help, I wanna pass this iready lesson or im going to get yelled at.

densk [106]

Answer:

1/10 is the correct answer

Step-by-step explanation:

3/5=6/10

7/10-6/10=1/10

7 0

2 years ago

Read 2 more answers

How literal equations and formulas are related

Margaret [11]

Answer:

A literal equation is an equation which consists primarily of letters. Formulas are an example of literal equations.

5 0

3 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

3 years ago