Answer:
3.8 = 38/10
Step-by-step explanation:
The given number = 3.8
We have to write 3.8 in fraction form a/b
Here we have 1 digit after the decimal. To get rid off the decimal number, we need to multiply both the numerator and the denominator by 10 since we have to 1 digit after the decimal.
= 38/10
Therefore, the answer is 3.8 = 38/10
Thank you.
Answer:
y = 18 and x = -2
Step-by-step explanation:
y = x^2+bx+c To find the turning point, or vertex, of this parabola, we need to work out the values of the coefficients b and c. We are given two different solutions of the equation. First, (2, 0). Second, (0, -14). So we have a value (-14) for c. We can substitute that into our first equation to find b. We can now plug in our values for b and c into the equation to get its standard form. To find the vertex, we can convert this equation to vertex form by completing the square. Thus, the vertex is (4.5, –6.25). We can confirm the solution graphically Plugging in (2,0) :
y=x2+bx+c
0=(2)^2+b(2)+c
y=4+2b+c
-2b=4+c
b=-2+2c
Plugging in (0,−14) :
y=x2+bx+c
−14=(0)2+b(0)+c
−16=0+b+c
b=16−c
Now that we have two equations isolated for b , we can simply use substitution and solve for c . y=x2+bx+c 16 + 2 = y y = 18 and x = -2
Answer:
You didnt give any options, but I'm guessing one of them has a 3 in the tens digits, which should be the right answer.
Step-by-step explanation:
Answer:
One
Step-by-step explanation:
Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)
To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.
Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.
