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sashaice [31]
3 years ago
11

Change the given quantity to the indicated unit. Round the answer to the nearest tenth of the unit if necessary.

Mathematics
1 answer:
dalvyx [7]3 years ago
4 0
Well 1 mile is approximately 1.6 so multiply 8 by 1.6 to get 12.8. The answer is A. 12.8km
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Answer:

There is really no substitute for reading this story. It's a classic, and gives some real insights into a culture where racial prejudice flourished, and how Scout's father stood against it.

Step-by-step explanation:

If you are reading, and have questions about what's going on, or what things mean, please ask.

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two models are shown. Each model has been shaded grey to represent a fraction. wgucj statement is true about the fractions 3/4 a
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The third, they are equivalent because the size of the shaded area is the same.

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3 years ago
6 + (9 − 1) 2 ÷ 4 <br> the 2 is an exponent
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4 0
3 years ago
A tank and a pail contained a total of 962 ml of water. When 250 ml of water was poured from the pail to the tank, the amount of
Allisa [31]

By solving a system of equations, we will see that the pail originally contained 382.9 ml.

<h3>How to write the system of equations?</h3>

First, we need to define the variables, we will use:

  • T = amount of water in the tank.
  • P = amount of water in the pail.

First, we know that the total amount of water is 962 ml, then we have:

P + T = 962 ml.

We also know that if we pour 250 ml from the pail to the tank, the amount of water in the tank will be 12 times the amount of water in the pail, this is written as:

T + 250ml = 12*(P - 250ml)

Then the system of equations is:

P + T = 962 ml

T + 250ml = 12*(P - 250ml)

To solve this, first, we need to isolate one of the variables in one of the equations, I will isolate T in the first one:

T = 962 ml - P

Now we replace this into the other equation to get:

(962 ml - P) + 250ml = 12*(P - 250ml)

Now we can solve this for P.

962 ml + 250 ml - P = 12*P - 12*250 ml

1,212 ml - P = 12*P - 3,000 ml

1,212  ml + 3,000 ml = 12*P - P

(4,212 ml)/11 = P = 382.9 ml

So the pail originally contained 382.9 ml

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
2 years ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
3 years ago
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