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irina1246 [14]
3 years ago
7

What is the area of triangle ABC if the height is 4 yards and the base is 15 yards

Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

The answer is 30yd²

Step-by-step explanation:

A=hb b/2

=4·15/2

=30yd²

irakobra [83]3 years ago
5 0

Answer:

30 square yards

Step-by-step explanation:

You can calculate the area of a triangle by using the formula: A = \frac{1}{2}bh, where b=base, and h=height, and since you have both values you can easily calculate the area by plugging the values in

Plug Values Into Equation:

A = \frac{1}{2}(15)(4)

Multiply 15 and 4

A=\frac{1}{2}(60)

Multiply by 1/2 (or technically divide by 2)

A = 30

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3 years ago
the Millers drove 105 miles on four gallons of gas.At this rate how many miles can they drive on six gallons of gas
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3 years ago
Find AA and BB that make the equation true. Verify your results.
CaHeK987 [17]

Answer:

a. A = -1 and B = 1

b. A = 7 and B = -5

Step-by-step explanation:

a.

\frac{A}{x+1} +\frac{B}{x-1}  = \frac{2}{x^2-1}

\frac{A*(x-1)+B*(x+1)}{(x+1)*(x-1)} = \frac{2}{x^2-1}

\frac{Ax - A + Bx + B}{x^2 -1} = \frac{2}{x^2-1}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 0

(A + B)x = 0

A + B = 0

A = -B

B - A = 2

B - (-B) = 2

2B = 2

B = 1  and A = -1

b.

\frac{A}{x+3} + \frac{B}{x +2} = \frac{2x -1}{x^2+5x+6}

\frac{A*(x+2) + B*(x+3)}{(x+3)*(x+2)} = \frac{2x-1}{x^2+5x+6}

\frac{Ax + 2A + Bx + 3B}{x^2 + 5x + 6} = \frac{2x-1}{x^2+5x+6}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 2x

(A + B)x = 2x

A + B = 2

A = 2 - B

2A + 3B = -1

2*(2-B) + 3B = -1

4 - 2B + 3B = -1

B = -5  and A = 2 - (-5) = 7

5 0
4 years ago
Why aren’t credit cards included in m1 or m2 definition of money?
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