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Trava [24]
3 years ago
12

HELP PLSS I DONT WANNA FAIL

Mathematics
1 answer:
posledela3 years ago
3 0

Answer: 1/2 and 3/6

Explanation: 1/2 is equal to 3/6 because if you divide both 3 and 6 by 2 it’s 1/2

Not sure about 4

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4 0
3 years ago
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Mr. Thompson has been asked to partition some space in a garage for storage. He estimates 6 square feet per individual will be r
gogolik [260]
The garage is 1800 sq feet.
4 0
3 years ago
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sharon earns $25 per item that she sells plus a base salary of $150 per week. write and solve an inequality to find how many ite
lozanna [386]
She has to sell 24 items
7 0
3 years ago
Please Show Work.
s344n2d4d5 [400]

Answer:

\huge\boxed{x=17}

Step-by-step explanation:

It's important to note that when two angles create a straight line, they are supplementary.

This means their angle measures add up to 180° since a 180° angle is a straight line.

Since we know the measures of both angles in equation form, we can add them together and have them equal 180 to solve for x.

(5x-18) + (4x+45) = 180

Combine like terms:

9x + 27 = 180

Subtract 27 from both sides:

9x = 153

Divide both sides by 9:

x = 17

So x = 17.

Hope this helped!

5 0
3 years ago
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A mole of 1 gallon cans of paint could cover every square inch of the surface of how many planets the size of the earth?
Nady [450]

Answer:

The answer is 4.4*10^1^0 planets

Step-by-step explanation:

We ll have to find more information first to solve this question.

1. One mole = 6.022 x 10^23

Assuming one gallon of paint covers the 400 sq ft of area.

Thus total area which can be covered by 1 mole of gallon is

=6.022*10^2^3 * 400\\=2.40*10^2^6

2. Now we will find the surface area of earth

Area = 4\pi R^2

The radius of earth is 2.1 x 10^7 Feet

substituting values

Area = 4*3.14*(2.1*10^7)^2\\Area = 5.5*10^1^5ft^2

3. Now we will find out the number of planets of earth size which can be covered by mole of gallon of paint

= Total area one mole of gallon can cover / area of earth

= 2.40 * 10^2^6/5.5*10^1^5\\=4.4*10^1^0 planets

6 0
4 years ago
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