This makes a right triangle with hypotenuse x+2 and legs 10 and x
10²+x²=(x+2)²
100 + x² = x²+4x+4
100=4x+4
4x=96
x=24, the height we are looking for
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
Answer:
Equivalent systems of equations review
Step-by-step explanation:
We're given two systems of equations and asked if they're equivalent.
x + 4y = 8 (1)
4x + y = 2 (2)
Interestingly, if we sum the equations in System A, we get:


Replacing the first equation in System A with this new equation, we get a system that's equivalent to System A:


This is System B, which means that System A is equivalent to System B.
Answer:
C
Step-by-step explanation: