Answer: where is the question??
Hello,
The sum of volumes of the two spheres is
4/3*π*a³+4/3*π*b³=4/3*π*c³
c=∛(a³+b³)=∛(3³+5³)=∛152=5.336803297...≈5.34 (cm)
Answer:
<em>Part A: 3,</em>
<em>Part B: - 4</em>
Step-by-step explanation:
<em>~ Part A ~ </em>
The problem would be in terms of such an expression: ( - 6 - ( - 3 )^2 )/ -5
Now knowing the expression, let us simplify in terms of basic algebra:
( -6 - 9 )/ -5 = ( - 15/ - 5 ) = <em>Answer; 3</em>
<em>~ Part B ~ </em>
We know the problem to be p^2/ r, but we must substitute the value of p being -10, and r ⇒ -25: ( - 10 )^2/ -25
Now let us simplify the expressions:
( - 10 )^2/ -25 = 100/ - 25 =<em> Answer; -4</em>
Answer:
16
Step-by-step explanation:
the answer is 16 I think
Formula is: h = vi · t + 1/2 g · t²
For the final position ( on the ground ): h = - 255 ft
vi = - 21 ft/s, g = -9.81 m/s² = - 32.174 ft/s²
- 255 = - 21 t - 1/2 · 32.174 t²
16.087 t² + 21 t - 255 = 0
t 1/2 = ( - 21 +/- √ (441 + 16,408.74 ))/ 32.174 =
= ( -21+/- 129.8 ) / 32.174 = 108.8 / 32.174 = 3.38 s
Answer: The ball hits the ground after 3.38 s.
