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Sophie [7]
3 years ago
10

Consider the function arctan(x/6)arctan⁡(x/6). write a partial sum for the power series which represents this function consistin

g of the first 5 nonzero terms. for example, if the series were ∑∞n=03nx2n∑n=0∞3nx2n, you would write 1+3x2+32x4+33x6+34x81+3x2+32x4+33x6+34x8. also indicate the radius of convergence.
Mathematics
1 answer:
Natali [406]3 years ago
3 0
<span>(x^2)/36 - (x^4)/1944 + (23x^6)/2099520 - (11x^8)/44089920 + (563x^10)/95234227200 radius of convergence = DNE (the series does not converge)</span>
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What is the midline of the function graphed below?<br><br> y = 1<br> y= 0.5<br> y = 0<br> y =2
8_murik_8 [283]

Answer:

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Step-by-step explanation:

42/2=21 or one triangles.

Using the <u>Pythagorean Theorem A^2+B^2=C^2</u>

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7 0
2 years ago
Enter the finite geometric series from its given description, and then enter its sum.
Mama L [17]

Answer:

a_n= 4(-5)^{(n-1)}

-10416

Step-by-step explanation:

a = 4

r = -5

geometric series:  a_n=ar^{(n-1)} = 4(-5)^{(n-1)}

Determine which term = -12500:

a_n=-12500

4(-5)^{(n-1)}=-12500

(-5)^{(n-1)} = -3125

(5)^{(n-1)} = 3125

(n-1)ln(5) = ln(3125)

n-1 = ln(3125)/ln(5) = 5

n = 5 + 1 = 6

a_6=-12500

Using geometric sum series formula: S_n=\frac{a(1-r^n)}{1-r}

Therefore, S_6=\frac{4(1-(-5)^6)}{1-(-5)} =\frac{-62496}{6} =-10416

4 0
3 years ago
Z + 81 = 9z -7 help solve
Ede4ka [16]
8z-7=81
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z=11
Have a good day!
:0)
5 0
3 years ago
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Round to the Nearest Ten
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Answer:

Step-by-step explanation:

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6 0
3 years ago
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