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shutvik [7]
2 years ago
8

Hii! would anyone mind helping me out?

Mathematics
1 answer:
Eduardwww [97]2 years ago
5 0

Answer:

(4, 4)

Step-by-step explanation:

This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola.

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Match the values in this hyperbola to those of the standard form. The variable h represents the x-offset from the origin, k represents the y-offset from origin, a.

a = 1

b = 3

k = 4

h = 4

Thus,

(x-4)^2 - \frac{(y-4)^2}{9} = 1

The center of a hyperbola follows the form of (h, k). Substitute in the values of h and k.

= (4, 4)

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Answer:

48 kg

Step-by-step explanation:

She can make 24 kg of dough in 3 hours

Multiply each by 2

She can make 24*2 kg of dough in 3*2 hours

She can make 48 kg of dough in 6 hours

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\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
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\end{cases}

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

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(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
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\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
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notice, the distance to B is exactly 6, and you know what that means.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
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notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.
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