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shutvik [7]
2 years ago
8

Hii! would anyone mind helping me out?

Mathematics
1 answer:
Eduardwww [97]2 years ago
5 0

Answer:

(4, 4)

Step-by-step explanation:

This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola.

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Match the values in this hyperbola to those of the standard form. The variable h represents the x-offset from the origin, k represents the y-offset from origin, a.

a = 1

b = 3

k = 4

h = 4

Thus,

(x-4)^2 - \frac{(y-4)^2}{9} = 1

The center of a hyperbola follows the form of (h, k). Substitute in the values of h and k.

= (4, 4)

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Nadusha1986 [10]

Answer:

Option 3 is correct that is (6+s)(s^2-6s+36)

Step-by-step explanation:

 We have general formula for sum of cube which is

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Here, we have a=s and b=6

on substituting the values in the formula we will get

6^3+s^3=(6+s)(s^2+6^2-6s)

After simplification we will get

6^3+s^3=(6+s)(s^2+36-6s)

After rearranging the terms we will get

6^3+s^3=(6+s)(s^2-6s+36) which exactly matches option 3 in the given options.

Therefore, option 3 is correct that is (6+s)(s^2-6s+36)



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4 years ago
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using a graphing tool  

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