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shutvik [7]
2 years ago
8

Hii! would anyone mind helping me out?

Mathematics
1 answer:
Eduardwww [97]2 years ago
5 0

Answer:

(4, 4)

Step-by-step explanation:

This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola.

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Match the values in this hyperbola to those of the standard form. The variable h represents the x-offset from the origin, k represents the y-offset from origin, a.

a = 1

b = 3

k = 4

h = 4

Thus,

(x-4)^2 - \frac{(y-4)^2}{9} = 1

The center of a hyperbola follows the form of (h, k). Substitute in the values of h and k.

= (4, 4)

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6x - 6x + 14 = 12
14 = 12 (incorrect)

when ur variables cancel out and u r left with an incorrect statement, this means there is no solution because ur lines are parallel

so ur answer is : no solution
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For the equation --4y = 8x, what is the constant of variation?
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Answer: 1) B is correct, constant of variation is -2.

Step-by-step explanation:

1)

Direct variation states that a relationship between the two variables. we say y varies directly as x

i.e,  or y =kx.................[1] ;  where k is the constant of variation.

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Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

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