2 1/10 as a percentage

Graph this parametric equation<br><br> x = 2t y = t + 5, -2 ≤ t ≤ 3

UNO [17]

We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem.

We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:

at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8

for the second equation

at t = -2 ; x = 2*-2 =-4
at t=3; x = 2*3 = 6

we group the points based on their original corresponding t's

(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.

6 0

3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm