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1 year ago

A shelf can be packed from end to end with 30 large books or 45 small books.

Mathematics

1 answer:

DerKrebs [107]1 year ago

4 0

Answer:

Step-by-step explanation:

since 30÷45 = 2/3 then

The space taken by a small book is equal to

the space taken by 2/3 a large book.

…………………………………………………

Calculating the number of large book corresponding to 23 small books :

= 23×(2÷3) + 3

= 18.333333333333 (large book)

Then ,Kevin can pack the shelf with (at most) : 30 - 19 = 11 more large books

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2 years ago

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If y is the circumcenter is angle STU find each measure

snow_tiger [21]

Answer:

Measures are SV=9 units., SY=14 units, YW= $\sqrt75units$ , YW= $\sqrt27units$

Step-by-step explanation:

Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.

As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.

Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.

Given ST=18 units.

As VY is perpendicular bisector implies SV=9 units.

Also in triangle VTY

$YT^{2}=VY^{2}+VT^{2}$

⇒ $14^{2}=VY^{2}+9^{2}$

⇒ VY^{2}=115

As vertices of triangle are equidistant from the circumcenter

⇒ SY=YT=UY=14 units

Hence, SY is 14 units

In ΔUWY, $UY^{2}=YW^{2}+UW^{2}$

⇒ $14^{2}=YW^2+11^{2}$

⇒ $YW^2=196-121=75$ ⇒ YW= $\sqrt75units$

In ΔYXU, $UY^{2}=YX^{2}+XU^{2}$

⇒ $14^{2}=YX^2+13^{2}$

⇒ $YX^2=196-169=27$ ⇒ YW= $\sqrt27units$

Hence, measures are SV=9 units., SY=14 units, YW= $\sqrt75units$ , YW= $\sqrt27units$

4 0

2 years ago

Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin

jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

GIVEN :-

There are 2 right-angled triangles.

In the triangle on the right side ,

Hypotenuse = 26m
Base = 10m

In the triangle on the left side ,

Base = 18m

TO FIND :-

Length of the common perpendicular to both triangles.
Length of the hypotenuse of the triangle on the left side.

FACTS TO KNOW BEFORE SOLVING :-

$Hypotenuse = \sqrt{Base^2 + Perpendicular^2}$ .
$Perpendicular = \sqrt{Hypotenuse^2 - Base^2}$

SOLUTION :-

In the triangle on the right side ,

$Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m$

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

$Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m$

∴ x = 30m

3 0

2 years ago

The area of a square can be tripled by increasing the length and width by 10 inches. What is the original length of the square?

trapecia [35]

The new square has length: 10 + l, where l is the original length of the square, and it's area is (10 + l)^2;
So, we solve the equation: 3 x l^2 = (10 + l)^2;
Then, 3 x l^2 = 100 + 20 x l + l^2;
Finally, 2xl^2 - 20xl - 100 = 0; / ÷2;
l^2 - 10l - 50 = 0 (we use the quadratic equation formula);
The only positive solution is l = 5(1+ \sqrt{3} );

5 0

2 years ago