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8090 [49]
2 years ago
10

Need help with Math (Quadratic)

Mathematics
1 answer:
BaLLatris [955]2 years ago
8 0

Answer:

  f(x) = 2(x -3)² +5   or   f(x) = 2x² -12x +23

Step-by-step explanation:

The equation of a quadratic is easily written in vertex form when the coordinates of the vertex are given. Here, the point one horizontal unit from the vertex is 2 vertical units higher, indicating the vertical scale factor is +2.

__

<h3>vertex form</h3>

The vertex form equation for a parabola is ...

  f(x) = a(x -h)² +k . . . . . . vertex (h, k); vertical scale factor 'a'

<h3>equation</h3>

For vertex (h, k) = (3, 5) and vertical scale factor a=2, the vertex form equation of the parabola is ...

  f(x) = 2(x -3)² +5 . . . . . vertex form equation

Expanded to standard form, this is ...

  f(x) = 2(x² -6x +9) +5

  f(x) = 2x² -12x +23 . . . . . standard form equation

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Red Lobster Bill is $43 Leaving a 15% tip What is the final bill?
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Answer:

49.45

Step-by-step explanation:

15% of 43 dollars is 6.45 and 43+6.45 is 49.45

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Find the angle between u=(8, -2) and v=(9,3) Round to the nearest tenth of a degree.
Kryger [21]

Answer:

the angle between u=(8, -2) and v=(9,3) is 32.5°

Step-by-step explanation:

u=(8,-2)=(u1,u2)→u1=8, u2=-2

v=(9,3)=(v1,v2)→v1=9, v2=3

We can find the angle between two vectors using the formula of dot product:

u . v =║u║║v║cos α   (1)

And the dot product is:

u . v = u1 v1 + u2 v2

u . v = (8)(9)+(-2)(3)

u . v = 72-6

u . v = 66


║u║=√(u1²+u2²)

║u║=√((8)²+(-2)²)

║u║=√(64+4)

║u║=√(68)

║u║=√((4)(17))

║u║=√(4)√(17)

║u║=2√(17)


║v║=√(v1²+v2²)

║v║=√((9)²+(3)²)

║v║=√(81+9)

║v║=√(90)

║v║=√((9)(10))

║v║=√(9)√(10)

║v║=3√(10)


Replacing the known values in the formula of dot product (1):

u . v =║u║║v║cos α

66 = 2√(17) 3√(10) cos α

Multiplying:

66 = 6√((17)(10)) cos α

66 = 6√(170) cos α

Solving first for cos α: Dividing both sides of the equation by 6√(170):

\frac{66}{6\sqrt{170} }=\frac{6\sqrt{170}cos \alpha}{6\sqrt{170} }

\frac{66}{6\sqrt{170}}=cos\alpha

Simplifying: Dividing the numerator and denominator on the left side of the equation by 6:

(66/6)/(6√170/6)=cosα→11/√170=cosα→cosα=11/√170

cosα=11/13.03840481→cosα=0.84366149

\alpha=cos^{-1}0.84366149\\\alpha=32.47119205^{\°}\\ \alpha=32.5^{\°}

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. Write the equation of the line with a slope of -3 and a y-intercept of 10
sergiy2304 [10]

The slope-intercept equation for a straight line as - 3 x + 10.

Slope refers to a number that describes both the direction and the steepness of the line.

The slope-intercept equation for a straight line is given by:

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Here, we are given that:

m = slope = -3

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Put it in the equation  y = m x + b, we get that:

y = (-3) x + 10

y = -3 x + 10.

Therefore, we get the slope-intercept equation for a straight line as - 3 x + 10.

Learn more about slopes here:

brainly.com/question/3493733

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