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1 year ago

7

Help picture below please

1 answer:

spayn [35]1 year ago

3 0

Answer:

tkm

Step-by-step explanation:

First T the middle k and at last m

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-4 x f (8) + 3 x g(-7) HELP ASAP

lubasha [3.4K]

Answer:

-32

Step-by-step explanation:

-4 + f(8) + 3 x g(-7) = ?

To find f(8), look at each of the f(x) function and find x = 8. The y value is the answer you will plug in for f(8). The same goes for g(-7), but you will be looking at the g(x) function at x = -7.

f(8) = -4

g(-7) = -8

Make sure you solve in the correct order using PEMDAS.

-4 + (-4) + 3 x (-8) = -32

8 0

2 years ago

Tanya is buying a skateboard for $42.38,a helmet for $17.60,and a set of elbows an nee pads for $12.89.She estimates the total c

Mila [183]

Her estimate is lower than her actual cost because her total is 72.87 she is off by 1.72 because she only added 42,17,and 12 and forgot all about adding the cent or the .60,.38,and the .89.

4 0

2 years ago

Circle P has a circumference of approximately 75 inches.

photoshop1234 [79]

Answer:

12in is you answer

Step-by-step explanation:

The formula to find circumference is $C=2\pi r$

so to rearrange to solve for radius that will be $r=\frac{C}{2\pi }$

= $\frac{75}{2\pi }$

=11.94in

5 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

so

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

On a horizontal number line, positive numbers are_____

Bond [772]

Answer:

the horizontal are called x-axis, while the vertical are called y-axis

8 0

2 years ago