Answer:
A. 1.3 bison/mi^2
Explanation:
4500 bison divided by 3472 sq miles is 1.3 bison per mile squared.
Answer:
The effects of supercritical CO2 (SC-CO2) on the microbiological, sensory (taste, odour, and colour), nutritional (vitamin C content), and physical (cloud, total acidity, pH, and °Brix) qualities of orange juice were studied. The CO2 treatment was performed in a 1 litre capacity double-walled reactor equipped with a magnetic stirring system. Freshly extracted orange juice was treated with supercritical CO2, pasteurised at 90°C, or left untreated. There were no significant differences in the sensory attributes and physical qualities between the CO2 treated juice and freshly extracted juice. The CO2 treated juice retained 88% of its vitamin C, while the pasteurised juice was notably different from the fresh juice and preserved only 57% of its vitamin C content. After 8 weeks of storage at 4°C, there was no microbial growth in the CO2 treated juice.
Answer:
it is phosphorus it has o most 2 times as much electromagnetically
Explanation:
Answer:
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Explanation:
Initially
3.0 atm 0
At equilibrium
(3.0-2p) p
Equilibrium partial pressure of 
p = 0.45 atm
The value of equilibrium constant wil be given by :
After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :
After adding 1.5 atm of 
:
(2.1+1.5) atm 0.45 atm
At second equilibrium:'
(3.6-2P) (0.45+P)
The expression of equilibrium can be written as:
Solving for P:
P = 0.37 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:
= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm
Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.
Answer:
0.375 mols
Explanation:
- Relative atomic mass Ar of C=12×1=12
- Relative atomic mass Ar of O=16×2=32
- Realitive formula mass Mr is 12+32=44
mol:mass
1 : 44
x :16.5
cross multiply and get the answer
