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Sidana [21]
4 years ago
13

Rank the following elements by increasing atomic radius: carbon, aluminum, oxygen, potassium. Rank the following elements by inc

reasing atomic radius: carbon, aluminum, oxygen, potassium. @Chemistry
Chemistry
1 answer:
Lapatulllka [165]4 years ago
8 0
The trend of atomic radius in the periodic table is increasing from right to left and from top to bottom. In reference to the table, oxygen has smaller radius compared to carbon, which is smaller than aluminum and which is also smaller than potassium. Thus, the trend from smallest to biggest is oxygen carbon, aluminum and potassium.
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Elements that share properties of both metals and nonmetals?
maw [93]
I can help with that!
<span>-Boron (B)
-Silicon (Si)
-Germanium (Ge)
-Arsenic (As)
-Antimony (Sb)
-Tellurium (Te)
-Polonium (Po)
<span>-Astatine (At)</span></span>
7 0
3 years ago
Read 2 more answers
Complete the table to summarize the properties of the different subatomic particles. Type in your answers.
Aloiza [94]

<h2>Complete the table to summarize the properties of the different subatomic particles. </h2>

Explanation:

Atom

It is a smallest particle which cant exist independently.

According To Dalton, atom was indivisible but later on, it was proved that atom can be subdivided into sub atomic particles called electron, proton & neutron.

These subatomic particles have marked properties .

Proton

  • It was discovered by E.Goldstein .
  • It is positively charged particle
  • It is present in nucleus .
  • Its mass is equal to 1.6726219 × 10⁻²⁷ kilograms

Neutron

  • It was discovered by E.chadwick .
  • It is neutral
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  • It's mass is equal to 1.674927471×10⁻²⁷ kg

Electron

  • It was discovered by J.J Thomson .
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  • It is present outside the nucleus in shells .
4 0
3 years ago
Read 2 more answers
Which best describes the molecules of an ideal gas
Serhud [2]
Options are as follow,

A)  <span>Constant volume, no intermolecular forces of attraction,energy loss in collisions 

B)  </span><span>No volume, strong intermolecular forces of attraction, perfectly elastic collisions

C)  </span><span>Constant volume, no intermolecular forces of attraction, energy gain during collisions

D)  </span><span>No volume, no intermolecular forces of attraction, perfectly elastic collisions

Answer:
            Option-D (</span>No volume, no intermolecular forces of attraction, perfectly elastic collisions) is the correct answer.

Explanation:
                   As we know there are no interactions between gas molecules due to which they lack shape and volume and occupies the shape and volume of container in which they are kept. So, we can skip Option-B. 
                   Secondly we also know that the gas molecules move randomly. They collide with the walls of container causing pressure and collide with each other. And these collisions are perfectly elastic and no energy is lost or gained during collisions. Therefore Option-A and C are skipped.
                   Now we are left with only Option-D, In option D it is given that ideal gas has no volume. This is true related to Ideal gas as it is stated in ideal gas theories that molecules are far apart from each other and the actual volume of gas molecules compared to volume of container is negligible. Hence, for ideal gas Option-D is a correct answer.
4 0
3 years ago
What are downbursts?
katovenus [111]
Downbursts are damaging winds<span> localized in an area which are caused by air that flows downward rapidly out from a thunderstorm. They can cause severe damage to infrastructures and can cause casualties when not prepared. This becomes worse as these types penetrate in areas near the ground. </span>
3 0
3 years ago
Using VSEPR model, how is the molecular arrangement about the central atom (molecular geometry) for XeF4?
jeka57 [31]

Answer:

Square planar.

Explanation:

Hello,

In this case, it can be demonstrated that the central atom Xenon in XeF₄ has a sp³d² hybridization which means that its geometry is likely to be octahedral.  Nevertheless Applying by applying the valence shell electron pair repulsion (VSEPR) model to in order to minimize the repulsion among lone pairs, bond pairs and lone pair-bond pairs, we we realize repulsion is actually minimized when lone pairs are anti to one another and the fluorine atoms are in equatorial position, for that reason, the corrected and properly exhibited geometry or molecular arrangement of the compound turns out square planar. You can verify it on the attached picture.

Regards.

8 0
3 years ago
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