Answer:
0.525 M CuSO
Explanation:
Molarity (M) is the units mol/L. Let's figure out how many moles of CuSO we have:
35 mL = 35/1000 L = 0.035 L
0.035 L * 1.50 mol/L = 0.0525 mol CuSO
Our new volume is 100 mL, so let's first convert this to L:
100 mL = 100/1000 L = 0.100 L
To find the new molarity, divide the number of moles (0.0525 moles) by the number of liters (0.100 L):
0.0525 mol / 0.100 L = 0.525 M CuSO
Hope this helps!
Answer:
<u>The half-reaction that occurs on the anode of an electrolytic cell is called oxidation.
</u>
This can easily be depicted by a chemical reaction as such <u>"Zn(s) = Zn2+ (aq) + (2e-)"
</u>
While, the Zinc in this reaction loses two elections. Hence copper gains those electrons and becomes solid.
<em>These reactions occurring on the anode are called positive reactions.
</em>
While the reaction that occurs on the cathode is called reduction. This reaction can be represented by this equation "<u>Cu2+ (aq) + 2e- = Cu(s)</u>".
<u>These non-spontaneous reactions occurring in an electrolytic cell together are called redox reactions. These generate electrical energy.</u>
Empirical formula = mol ratio
mol H = 9.42 x 10²⁴ : 6.02 x 10²³ = 15.648
mol N = 3/9 x 15.648 = 5.216
mass N = 5.216 x 14 g/mol =73.024 g
Answer:
Mass = 30.104 g
Explanation:
Given data:
Volume of Cl₂ = 8.80 L
Pressure = 890 torr (890/760 = 1.17 atm)
Temperature = 23°C (23+273 = 296K)
Mass of chlorine = ?
Solution:
PV = nRT
n = PV/RT
n = 1.17 atm × 8.80 L / 0.0821 atm. L. k⁻¹.mol⁻¹ × 296K
n = 10.296 atm. L / 24.30 atm. L.mol⁻¹
n = 0.424 mol
Mass of chlorine:
Mass = number of moles × molar mass
Mass = 0.424 mol × 71 g/mol
Mass = 30.104 g
